问题
I need to check to see if a string contains at least one number in it using Ruby (and I assume some sort of regex?).
How would I do that?
回答1:
You can use the String
class's =~
method with the regex /\d/
as the argument.
Here's an example:
s = 'abc123'
if s =~ /\d/ # Calling String's =~ method.
puts "The String #{s} has a number in it."
else
puts "The String #{s} does not have a number in it."
end
回答2:
Alternatively, without using a regex:
def has_digits?(str)
str.count("0-9") > 0
end
回答3:
if /\d/.match( theStringImChecking ) then
#yep, there's a number in the string
end
回答4:
Rather than use something like "s =~ /\d/", I go for the shorter s[/\d/] which returns nil for a miss (AKA false in a conditional test) or the index of the hit (AKA true in a conditional test). If you need the actual value use s[/(\d)/, 1]
It should all work out the same and is largely a programmer's choice.
回答5:
!s[/\d/].nil?
Can be a standalone function -
def has_digits?(s)
return !s[/\d/].nil?
end
or ... adding it to the String class makes it even more convenient -
class String
def has_digits?
return !self[/\d/].nil?
end
end
来源:https://stackoverflow.com/questions/2224790/how-do-i-check-if-a-string-has-at-least-one-number-in-it-using-ruby