问题
I want to define an operator<< for all enums, to cout the value and print that it is an enum like this:
code:
enum AnyEnum{A,B,C};
AnyEnum enm = A;
cout << enm <<endl;
output:
This is an enum which has a value equal to 0
I know a way of doing this with Boost library by using is_enum struct. But I don’t understand how it works. So that's why, in general, I am interested how to identify if the veriable is a class type, union type or an enum (in compile time).
回答1:
Determining class types you could use the fact that member pointers exist
template<typename A, typename B>
struct issame { };
template<typename A>
struct issame<A, A> { typedef void type; };
template<typename> struct tovoid { typedef void type; };
template<typename T, typename = void>
struct isclass { static bool const value = false; };
template<typename C>
struct isclass<C, typename tovoid<int C::*>::type> {
static bool const value = true;
};
You cannot detect the difference of an union and a non-union class. At least I don't know how, and boost doesn't know either.
I think detecting enums could work by making sure T
isn't a class, function or integral type, and then trying to assign to an integral type. You could
template<typename E, typename = void>
struct isenum {
struct No { char x; };
struct Yes { No n1; No n2; };
struct nullsink {};
static No checkI(nullsink*); // accept null pointer constants
static Yes checkI(...);
static Yes checkE(int);
static No checkE(...);
static bool const value = (sizeof(checkI(E())) == sizeof(Yes)) &&
(sizeof(checkE(E())) == sizeof(Yes));
};
// class
template<typename E>
struct isenum<E, typename tovoid<int E::*>::type> {
static bool const value = false;
};
// reference
template<typename R>
struct isenum<R&, void> {
static bool const value = false;
};
// function (FuntionType() will error out).
template<typename F>
struct isenum<F, typename issame<void(F), void(F*)>::type> {
static bool const value = false;
};
// array (ArrayType() will error out)
template<typename E>
struct isenum<E[], void> {
static bool const value = false;
};
template<typename E, int N>
struct isenum<E[N], void> {
static bool const value = false;
};
Quick & dirty test (works on GCC/clang/comeau):
enum A { };
struct B { };
typedef int &C;
typedef void D();
typedef int E;
typedef long F;
typedef int const G;
typedef int H[1];
template<typename T, bool E>
struct confirm { typedef char x[(T::value == E) ? 1 : -1]; };
int main() {
confirm< isenum<A>, true >();
confirm< isenum<B>, false >();
confirm< isenum<C>, false >();
confirm< isenum<D>, false >();
confirm< isenum<E>, false >();
confirm< isenum<F>, false >();
confirm< isenum<G>, false >();
confirm< isenum<H>, false >();
}
回答2:
I am interested how to identify if the veriable is a class type, union type or an enum (in compile time).
boost::type_traits
Even C++ TR1 has got a <type_traits>
header to support that functionality. In C++0x everything's gonna be a lot better.
For example the following machinery makes use of SFINAE to check whether the argument passed is a class type:
template<typename T>struct Check_If_T_Is_Class_Type
{
template<typename C> static char func (char C::*p);
template<typename C> static long func (...);
enum{val = CHECKER(func,Check_If_T_Is_Class_Type)};
};
The MACRO CHECKER
is
#define CHECKER(func_name,class_name) \
sizeof(class_name<T>::template func_name<T>(0)) == 1
To understand how type_traits work you need to have some basic knowledge of templates including template metaprogramming and SFINAE.
回答3:
This is usually done with compiler hooks. The compiler has special functions that "fill" the template with the apropriate value (at least in C++0x where type_traits has been standardized).
For instance the is_pod
trait uses the __is_pod
compiler hook under VC 10 to get the apropriate information.
回答4:
its not possible to know the variable type at compile time.
来源:https://stackoverflow.com/questions/4705316/how-to-know-if-the-argument-that-is-passed-to-the-function-is-a-class-union-or