问题
I was curious why a lambda with a return type can not be casted to a Runnable whereas a non void method reference can.
Runnable r1 = () -> 1; // not allowed
// error: incompatible types: bad return type in lambda expression
// int cannot be converted to void
Runnable r2 = ((Supplier)() -> 1)::get; // allowed
回答1:
The Runnable interface defines the run method with return type void. In a lambda expression that means that the part following the arrow -> must be a statement. This is explained in JLS §15.27.3:
If the function type's result is void, the lambda body is either a statement expression (§14.8) or a void-compatible block.
The JLS $14.5 clearly defines the syntax of a statement. As explained above it must be an "ExpressionStatement" (§ 14.8). Looking there, you can find that a simple literal is not an adequate expression, but a method invocation is (even if it returns something).
回答2:
This is not really a “special” rule for Lambdas. It has always been acceptable to use a non-void method in a statement context (in which case, the return value is thrown away), but not so with a simple expression. For instance “String.valueOf(true);” is a valid java statement, that may occupy a line by itself, whereas “true;” is not and may not.
来源：https://stackoverflow.com/questions/36696340/lambda-casting-rules