问题
I'm trying to use a function in order to get this working:
<img src='login.php?image=ind_legend.jpg'>
But I can't pass through the function to place the image. I went back a couple of steps and tried only this part of the code:
<?php
$file = "http://localhost/sales/test.jpg";
header('Content-type: image/jpeg');
readfile($file);
?>
or using this function:
echo file_get_contents($source);
but the fact is that the only thing I get is a broken image cross (IE) or nothing in Firefox.
I would appreciate any suggestions
Thanks in advance
回答1:
You certainly have some whitespace in your PHP script, or a UTF-8 BOM invisibly before your <?php
opening marker. Use a hexeditor to find out.
To debug it further, open the image URL http://localhost/login.php?image=ind_legend.jpg directly in your browser, save the file. And then compare it to the original JPEG.
回答2:
use the ob_clean() function of php before the readfile()
回答3:
As previously mentioned, you probably have some whitespace. I'd try replacing the entire file with the code below. Removing the closing php statement eliminates any chance that there is extra whitespace:
<?php
$file = "http://localhost/sales/test.jpg";
header('Content-type: image/jpeg');
readfile($file);
回答4:
first of all point your browser to http://youraddress/login.php?image=ind_legend.jpg and check the result.
Maybe the file /sales/test.jpg is corrupted or you don't have enabled the http:// wrapper for readline
At last save the corrupted image via the save image as... context menu option of your browser of choice and try to open it with a text editor. I will not surprised if you will find an error message (if you have them enabled).
来源:https://stackoverflow.com/questions/5877138/broken-image-with-readfile-and-file-get-contents