问题
Say we have two arrays:
double *matrix=new double[100];
double *array=new double[10];
And we want to copy 10 elements from matrix[80:89] to array using memcpy.
Any quick solutions?
回答1:
It's simpler to use std::copy:
std::copy(matrix + 80, matrix + 90, array);
This is cleaner because you only have to specify the range of elements to be copied, not the number of bytes. In addition, it works for all types that can be copied, not just POD types.
回答2:
memcpy(array, &matrix[80], 10*sizeof(double));
But (since you say C++) you'll have better type safety using a C++ function rather than old C memcpy:
#include <algorithm>
std::copy(&matrix[80], &matrix[90], array);
Note that the function takes a pointer "one-past-the-end" of the range you want to use. Most STL functions work this way.
回答3:
memcpy(array, matrix+80, sizeof(double) * 10);
来源：https://stackoverflow.com/questions/3902215/using-memcpy-to-copy-a-range-of-elements-from-an-array