java- how to generate a random hexadecimal value within specified range of values

问题

I have a scenario in a java web app, where a random hexadecimal value has to be generated. This value should be within a range of values specified by me. (The range of values can be hexadecimal or integer values).

What is the most efficient way to do this> Do I have to generate a random decimal number, and then convert it to hexadecimal? Or can a value be directly generated?

回答1:

Yes, you just generate a decimal value in your range. Something such as:

Random rand = new Random();
int myRandomNumber = rand.nextInt(0x10) + 0x10; // Generates a random number between 0x10 and 0x20
System.out.printf("%x\n",myRandomNumber); // Prints it in hex, such as "0x14"
// or....
String result = Integer.toHexString(myRandomNumber); // Random hex number in result

Hex and decimal numbers are handled the same way in Java (as integers), and are just displayed or inputted differently. (More info on that.)

回答2:

Try this,

String s = String.format("%x",(int)(Math.random()*100));
System.out.println(s);

回答3:

Random randomService = new Random();
StringBuilder sb = new StringBuilder();
while (sb.length() < RANDOM_HEX_LENGTH) {
    sb.append(Integer.toHexString(randomService.nextInt()));
}
sb.setLength(RANDOM_HEX_LENGTH);
System.out.println(sb.toString());

回答4:

Using Math.sin() (colors adaptable to totalItems to be colored):

double rFactor=0;
double gFactor=0.5;
double bFactor=1;
double rAdd=0.1;
double gAdd=0.2;
double bAdd=0.3;
String lettersLight[] = "6789ABCDEF".split("");
String lettersDark[] =  "0123456789".split("");
int halfLetters=lettersDark.length/2;

private void initRandomColor2(int totalItems) {
    double rFactor=0;
    double gFactor=(Math.PI/totalItems)*2;
    double bFactor=(Math.PI/totalItems)*4;
    rAdd=(Math.PI/totalItems)+(Math.PI/totalItems);
    gAdd=(Math.PI/totalItems)+(Math.PI/totalItems)*2;
    bAdd=(Math.PI/totalItems)+(Math.PI/totalItems)*4;
}
private String getRandomColor2(boolean light) {
    int r=(int)(halfLetters+(Math.sin(rFactor)*(halfLetters-1)));
    int g=(int)(halfLetters+(Math.sin(gFactor)*(halfLetters-1)));
    int b=(int)(halfLetters+(Math.sin(bFactor)*(halfLetters-1)));
    rFactor+=rAdd;
    gFactor+=gAdd;
    bFactor+=bAdd;
    return (light
            ?lettersLight[r]+lettersLight[r]+lettersLight[g]+lettersLight[g]+lettersLight[b]+lettersLight[b]
            :lettersDark[r]+lettersDark[r]+lettersDark[g]+lettersDark[g]+lettersDark[b]+lettersDark[b]
            );
}

回答5:

You can try this. As this works for me:

Random random = new Random();
int nextInt = random.nextInt(256*256*256);
System.out.println(String.format("#%06x", nextInt));

回答6:

Random progressive hex colors:

String letters[] = "0123456789ABCDEF".split("");
int min=letters.length-(letters.length/3);
int max=letters.length;
Random rnd=new Random(1000);
String colorEx[]= new String[]{"00","00","00"};
int colorChange=0;
int addColorChange=1;

private String getRandomColor() {
    StringBuilder color = new StringBuilder("#");
    int highColor=rnd.nextInt(2)+1;
    for (int i = 0; i<3; i++) {
        int addColor=0;
        if (i==highColor)
            highColor=min;

        color.append(colorEx[i]);

        if (colorChange==i) {
            if (colorEx[i].equals("00"))
                colorEx[i]="55";
            else if (colorEx[i].equals("55"))
                colorEx[i]="AA";
            else if (colorEx[i].equals("AA"))
                colorEx[i]="FF";
            else {
                if (i>0 && !"00".equals(colorEx[i-1]))
                    colorEx[i-1]="00";
                else if (i<2)
                    colorEx[i+1]="00";
                colorChange+=addColorChange;
                //colorChange++;
                if (colorChange>2 || colorChange<0) {
                    //colorChange=0;
                    addColorChange=-addColorChange;
                    colorChange+=addColorChange;
                    colorChange+=addColorChange;
                }
            }
        }
    }
    return color.toString();
}

来源：https://stackoverflow.com/questions/11094823/java-how-to-generate-a-random-hexadecimal-value-within-specified-range-of-value

标签

java

hex

decimal