Division in Python 3 gives different result than in Python 2

问题

In the following code, I want to calculate the percent of G and C characters in a sequence. In Python 3 I correctly get 0.5, but on Python 2 I get 0. Why are the results different?

def gc_content(base_seq):
    """Return the percentage of G and C characters in base_seq"""
    seq = base_seq.upper()
    return (seq.count('G') + seq.count('C')) / len(seq)

gc_content('attacgcg')

回答1:

/ is a different operator in Python 3; in Python 2 / alters behaviour when applied to 2 integer operands and returns the result of a floor-division instead:

>>> 3/2   # two integer operands
1
>>> 3/2.0 # one operand is not an integer, float division is used
1.5

Add:

from __future__ import division

to the top of your code to make / use float division in Python 2, or use // to force Python 3 to use integer division:

>>> from __future__ import division
>>> 3/2    # even when using integers, true division is used
1.5
>>> 3//2.0 # explicit floor division
1.0

Using either of these techniques works in Python 2.2 or newer. See PEP 238 for the nitty-gritty details of why this was changed.

回答2:

In python2.x / performs integers division.

>>> 3/2
1

To get desired result you can change either one of the operands to a float using float():

>>> 3/2.      #3/2.0
1.5
>>> 3/float(2)
1.5

or use division from __future__:

>>> from __future__ import division
>>> 3/2
1.5

回答3:

For Python2 / is integer division when the numerator and denominator are both int, you need to make sure to force floating point division

eg.

return (seq.count('G') + seq.count('C')) / float(len(seq))

alternatively, you can put

from __future__ import division

at the top of the file

来源：https://stackoverflow.com/questions/17531874/division-in-python-3-gives-different-result-than-in-python-2