How to dereference a memory location from python ctypes?

瘦欲@ 提交于 2019-12-28 06:01:34

问题


I want to replicate the following c code in python ctypes:

main() {
  long *ptr = (long *)0x7fff96000000;
  printf("%lx",*ptr);
}

I can figure out how to call this memory location as a function pointer but not just do a normal dereference:

from ctypes import *
"""
>>> fptr = CFUNCTYPE(None, None)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/ctypes/__init__.py", line 104, in CFUNCTYPE
    class CFunctionType(_CFuncPtr):
TypeError: Error when calling the metaclass bases
    item 1 in _argtypes_ has no from_param method
"""
fptr = CFUNCTYPE(None, c_void_p) #add c_void_p since you have to have an arg
fptr2 = fptr(0x7fff96000000)
fptr2(c_void_p(0))
#python: segfault at 7fff96000000 ip 00007fff96000000

Since there it is a segfault with the instruction pointer pointing to this memory location it is successfully calling it. However I can't get it to just read the memory location:

ptr = POINTER(c_long)
ptr2 = ptr(c_long(0x7fff96000000))
#>>> ptr2[0]
#140735709970432
#>>> hex(ptr2[0])
#'0x7fff96000000'
#>>> ptr2.contents
#c_long(140735709970432)

回答1:


ctypes.cast.

>>> import ctypes
>>> c_long_p = ctypes.POINTER(ctypes.c_long)
>>> some_long = ctypes.c_long(42)
>>> ctypes.addressof(some_long)
4300833936
>>> ctypes.cast(4300833936, c_long_p)
<__main__.LP_c_long object at 0x1005983b0>
>>> ctypes.cast(4300833936, c_long_p).contents
c_long(42)


来源:https://stackoverflow.com/questions/1555944/how-to-dereference-a-memory-location-from-python-ctypes

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