问题
I have a function:
myFunction (MyProc callback, void * ref)
This function is called from within an Objective-C class. The function is passed a pointer to the callback (a function in the class) and a reference. The reference is necessary because the callback is called statically and therefore doesn't have a context. The ref can be used to provide a context to the callback.
I want to be able to pass the Objective-C class as the reference. So the question is:
How do I cast an NSObject to a void * and how do I cast a void * as an NSObject.
Thanks in advance.
回答1:
Do something like this:
void func(void *q)
{
NSObject* o = CFBridgingRelease(q);
NSLog(@"%@", o);
}
int main(int argc, const char * argv[])
{
@autoreleasepool {
NSObject* o = [NSObject new];
func((void*)CFBridgingRetain(o));
}
return 0;
}
Note that CFBridgingRetain()
and CFBridgingRelease()
are macros around compiler attributes. Feel free to use either. I like the API variant as it is in more common use in our codebases and it is more explicitly / less confusing.
CFBridgingRetain()
effectively hard-retains the object that must be balanced by a CFBridgingRelease()
. It also happens to return a CFTypeRef
which is compatible with a cast to void*
. CFBridgingRelease()
effectively undoes that hard-retain and, thus, q
will only remain valid within the scope that o
is valid.
Valid for basic callbacks, but you'd probably not what that with a void *context;
type thing that has to stick around for a while. For that:
void callback(void *context)
{
// grab an ARC aware reference without impacting hard-retain
NSObject* o = (__bridge NSObject *)(context);
NSLog(@"%@", o);
}
void freeContext(void *context)
{
// release the hard-retain
CFBridgingRelease(context);
}
Note that Xcode is quite good about suggesting exactly what you should do if you leave out the cast / API call. It even explains the meanings of each of the alternative solutions (I relied on this heavily until I could keep 'em straight in my head).
回答2:
I assume you are using ARC. You can use something like this when calling myFunction
id ref = ...; // your Objective-C object
myFunction(callback, (__bridge_retained void *) ref);
In your callback, you must transfer the ownership back:
void callback(void* refPtr) {
id refObj = (__bridge_transfer id) refPtr;
}
Replace id
with your object type as appropriated.
回答3:
Answer: in no way. void *
is implicitly compatible with any pointer type, so if you have an object, which is a pointer of type id
(alias for struct objc_object *
), you can simply pass it where the void pointer is needed, without casting. Example:
// this is the declaration of the callback function:
void callback(void *context);
// then you can call it like this:
SomeClass *obj = [[SomeClass alloc] init];
callback(obj);
来源:https://stackoverflow.com/questions/12916491/pass-an-objective-c-object-to-a-function-as-a-void-pointer