问题
My code is as follows:
public static void Output<T>(IEnumerable<T> dataSource) where T : class
{
dataSourceName = (typeof(T).Name);
switch (dataSourceName)
{
case (string)typeof(CustomerDetails).Name.ToString(); :
var t = 123;
break;
default:
Console.WriteLine("Test");
}
}
But this is not working. The case statement is giving me an error saying that a constant variable is expected. Please help guys thank you!
回答1:
See C# switch statement limitations - why?
Basically Switches cannot have evaluated statements in the case statement. They must be statically evaluated.
回答2:
You can only match to constants in switch statements.
Example:
switch (variable1)
{
case 1: // A hard-coded value
// Code
break;
default:
// Code
break;
}
Successful!
switch (variable1)
{
case variable2:
// Code
break;
default:
// Code
break;
}
CS0150 A constant value is expected.
回答3:
You can't use a switch statement for this as the case values cannot be evaluated expressions. For this you have to use an an if/else ...
public static void Output<T>(IEnumerable<T> dataSource) where T : class
{
dataSourceName = (typeof(T).Name);
if(string.Compare(dataSourceName, typeof(CustomerDetails).Name.ToString(), true)==0)
{
var t = 123;
}
else if (/*case 2 conditional*/)
{
//blah
}
else
{
//default case
Console.WriteLine("Test");
}
}
I also took the liberty of tidying up your conditional statement. There is no need to cast to string after calling ToString()
. This will always return a string anyway. When comparing strings for equality, bare in mind that using the == operator will result in a case sensitive comparison. Better to use string compare = 0 with the last argument to set case sensitive on/off.
回答4:
switch is very picky in the sense that the values in the switch must be a compile time constant. and also the value that's being compared must be a primitive (or string now). For this you should use an if statement.
The reason may go back to the way that C handles them in that it creates a jump table (because the values are compile time constants) and it tries to copy the same semantics by not allowing evaluated values in your cases.
回答5:
Johnnie, Please go through msdn guide on switch. Also, the C# language specification clearly defines the compile time error case:
• If the type of the switch expression is sbyte, byte, short, ushort, int, uint, long, ulong, bool, char, string, or an enum-type, or if it is the nullable type corresponding to one of these types, then that is the governing type of the switch statement.
• Otherwise, exactly one user-defined implicit conversion (§6.4) must exist from the type of the switch expression to one of the following possible governing types: sbyte, byte, short, ushort, int, uint, long, ulong, char, string, or, a nullable type corresponding to one of those types.
• Otherwise, if no such implicit conversion exists, or if more than one such implicit conversion exists, a compile-time error occurs.
Hope this helps.
回答6:
This seems to work for me at least when i tried on visual studio 2017.
public static class Words
{
public const string temp = "What";
public const string temp2 = "the";
}
var i = "the";
switch (i)
{
case Words.temp:
break;
case Words.temp2:
break;
}
回答7:
Now you can use nameof
:
public static void Output<T>(IEnumerable<T> dataSource) where T : class
{
string dataSourceName = typeof(T).Name;
switch (dataSourceName)
{
case nameof(CustomerDetails):
var t = 123;
break;
default:
Console.WriteLine("Test");
}
}
nameof(CustomerDetails)
is basically identical to the string literal "CustomerDetails"
, but with a compile-time check that it refers to some symbol (to prevent a typo).
nameof
appeared in C# 6.0, so after this question was asked.
来源:https://stackoverflow.com/questions/7593377/switch-case-in-c-sharp-a-constant-value-is-expected