问题
This is ugly. What's a more Pythonic way to do it?
import datetime
t= (2010, 10, 2, 11, 4, 0, 2, 41, 0)
dt = datetime.datetime(t[0], t[1], t[2], t[3], t[4], t[5], t[6])
回答1:
Generally, you can use the func(*tuple) syntax. You can even pass a part of the tuple, which seems like what you're trying to do here:
t = (2010, 10, 2, 11, 4, 0, 2, 41, 0)
dt = datetime.datetime(*t[0:7])
This is called unpacking a tuple, and can be used for other iterables (such as lists) too. Here's another example (from the Python tutorial):
>>> range(3, 6) # normal call with separate arguments
[3, 4, 5]
>>> args = [3, 6]
>>> range(*args) # call with arguments unpacked from a list
[3, 4, 5]
回答2:
Refer https://docs.python.org/2/tutorial/controlflow.html#unpacking-argument-lists
dt = datetime.datetime(*t[:7])
来源：https://stackoverflow.com/questions/2238355/what-is-the-pythonic-way-to-unpack-tuples