Display current time in epoch

问题

I'm trying to display the current time in epoch, i'm not sure if this is correct, but i'm sure it's not since it's giving me an error:

NSDate *currentDate = [NSDate date];
NSDate *epochDate = [NSDate dateWithTimeIntervalSince1970:currentDate];

Any idea of how to accomplish this?

回答1:

NSString *epochTime = @"1347522689";
NSTimeInterval epochInterval = [epochTime longLongValue];
NSDate *epochNSDate = [[NSDate alloc] initWithTimeIntervalSince1970:epochInterval];
NSDateFormatter *dateFormatterEpoch = [[NSDateFormatter alloc] init];
[dateFormatterEpoch setDateFormat:@"yyyy-MM-dd HH:mm:ss zzz"];
NSString *epochDate = [dateFormatterEpoch stringFromDate:epochNSDate];

NSDate *currentDateNSDate = [NSDate date];
NSDateFormatter *dateFormatterCurrent = [[NSDateFormatter alloc] init];
[dateFormatterCurrent setDateFormat:@"yyyy-MM-dd HH:mm:ss zzz"];
NSString *currentDate = [dateFormatterCurrent stringFromDate:currentDateNSDate];


NSLog(@"epochDate = %@",epochDate);
NSLog(@"currentDate = %@", currentDate);

NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];

NSUInteger unitFlags = NSMonthCalendarUnit | NSDayCalendarUnit | NSYearCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit;

NSDateComponents *components = [gregorian components:unitFlags fromDate:epochNSDate toDate:currentDateNSDate options:0];

NSInteger year = [components month];
NSInteger months = [components month];
NSInteger days = [components day];
NSInteger hours = [components hour];
NSInteger min = [components minute];
NSInteger sec = [components second];


NSLog(@"Year Difference = %@\n Month Difference = %@\n, Days Difference = %@\n, Hours Difference = %@\n ,Minutes Difference = %@\n second Difference = %@\n", [[NSNumber numberWithInteger:year] stringValue] ,[[NSNumber numberWithInteger:months] stringValue], [[NSNumber numberWithInteger:days] stringValue], [[NSNumber numberWithInteger:hours] stringValue], [[NSNumber numberWithInteger:min] stringValue],[[NSNumber numberWithInteger:sec] stringValue]);

回答2:

NSTimeInterval epoch = [[NSDate date] timeIntervalSince1970];
NSLog(@"%f", epoch);

Or better yet, this gives just the integer part of the time:

int epoch = round([[NSDate date] timeIntervalSince1970]);
NSLog(@"%d", epoch);

回答3:

For converting your date to epoch. you need to use dateWithTimeIntervalSince1970 method like this below

NSDate *date = [NSDate date];
NSLog(@"epochDate: %f",([date timeIntervalSince1970]);

来源：https://stackoverflow.com/questions/22885867/display-current-time-in-epoch