问题
If I have the two following statements:
// OK
const int ARRAYSIZE = 5;
int x[ARRAYSIZE];
// NOT OK
int ARRAYSIZEBAD = 5;
int y[ARRAYSIZEBAD];
And I don't compile with the -pedantic-errors flag... why is the second example a bad thing? In what situation would it be preferable to use dynamic allocation with the new operator?
回答1:
C++ Why are non-const array declarations bad?
Because the length of the array must be known at the time of compilation. If a variable is non-const, then its value could change at run time, and thus would not be known at compile time. Only a compile time constant expression can be used as the length of an array - thus a const variable can only be used as the length of an array after its initialiser has been observed.
int[ARRAYSIZE] is a type. The requirement that size is known at compile time extends to all types that you instantiate, not just array types.
In what situation would it be preferable to use dynamic allocation ...
You need dynamic allocation when you don't know the length of the array at compile time.
You also need non-automatic allocation when the array is big. This is because the memory reserved for automatic allocation is often quite limited.
... with the new operator?
It's rarely preferable to allocate dynamic memory using a new-expression. std::vector is typically used when dynamic array is needed.
回答2:
As a couple of people of people have pointed out, C++ usually determines array sizes at compile time, not run time.
A variable has its value set at runtime, so there is no way to determine the size at compile time. That is, except for constant variables. Constant variables have a constant value through the entire program, and, thus, can be determined at compile time.
If you need an array that has a dynamic size, you have the option of the new keyword:
int* y = new int[mySize];
Of course, when you're done with it, you should delete it as well.
delete[] y;
Edit: Thanks to @WhozCraig who reminded me/pointed out that you have an even better option than new/delete. You can also use vector as well.
To use, just include <vector>
#include <vector>
and you can use it like this:
std::vector<int> y; // replace int with any type of object you want
This will allow you to dynamically modify the size of your "array" (so to speak) any time you want.
回答3:
The reason it's bad is that it's not valid C++ code. Some C++ compilers will compile it because of support for Variable-Length-Arrays (VLAs), but this is not a core supported C++ language feature and will not work on all Standard-conforming compilers.
In C++, if you know at compile-time the length of an array, you should use std::array<int, 5>, which is a replacement for and strictly better version of the "C-style array", i.e. int arr[5];. If you do not know the length at compile-time, and have to determine it at run-time, you should use std::vector<int>, which is a replacement for int* arr = new int[5];, and which has the added benefit that you don't need to remember to call delete[] later on, as the vector object will make sure the deleter is correctly called if the object goes out of stack.
回答4:
Remember: C and C++ are not Java. Arrays, for instance, are just a pointer to N pieces of memory. They are not Objects where you could store additional information, such as the size of the array. Thus, the compiler needs to know the size.
The reason isn't obvious for vectors. After all, you can use int * instead and then allocate whatever size you want.
But if you have a multi-dimensional array, it becomes more obvious why the compiler must know the size.
int myArray[3][3];
This is still just 9 ints of memory stored in the order of [0][0], [0][1], [0][2], [1][0] etc. So to get to myArray[2][1], the compiler knows to go to the 8th integer.
But here's a little more info on why it matters for 1-D arrays.
int myArray[10];
int myNextArray[5];
In this case, you have two pieces of memory, one that's 10 ints long and one that's 5 ints long. If the compiler doesn't know the size of them, how will it know how much space they each take, so it knows how to set up at the start of your method?
Or imagine this.
int size = 10;
int myArray[size];
size = 20;
How big is the array?
If you need dynamic arrays, use dynamic arrays.
来源：https://stackoverflow.com/questions/54871933/c-why-are-non-const-array-declarations-bad