What would be the right way to declare an array within a script that will be called by cron?

问题

I have written a KornShell (ksh) script that sets an array the following way:

set -A fruits Apple Orange Banana Strawberry

but when I am trying to run it from within cron, it raises the following error:

Your "cron" job on myhost
/myScript.sh

produced the following output:

myScript.sh: -A: bad option(s)

I have tried many crontab syntax variants, such as:

Attempt 1:

0,5,10,15,20,25,30,35,40,45,50,55 * * * * /path/to/script/myScript.sh

Attempt 2:

0,5,10,15,20,25,30,35,40,45,50,55 * * * * /path/to/script/./myScript.sh

Attempt 3:

0,5,10,15,20,25,30,35,40,45,50,55 * * * * cd /path/to/script && ./myScript.sh

Any workaround would be sincerely appreciated. Thanks much in advance!

回答1:

*/5 * * * * cd /path/to/script && ksh ./myScript.sh :- it will run every 5 mins. Define Path variables also in the cron itself.

回答2:

Does myScript.sh start with

#!/bin/ksh

(or whatever the path is for your ksh)?

回答3:

Although I'm not sure it's the best way to do it, I've managed to solve it this way:

Attempt 4:

0,5,10,15,20,25,30,35,40,45,50,55 * * * * cd /path/to/script && ksh ./myScript.sh

来源：https://stackoverflow.com/questions/306531/what-would-be-the-right-way-to-declare-an-array-within-a-script-that-will-be-cal