问题
I was reading the re-introduction to JavaScript on the MDN website and came across this example in the Array section:
for (var i = 0, item; item = a[i++];){
// Do something with item
}
Where "a[]" is an array being looped over.
I am confused about the value that "item" will have in its first iteration. As i=0 and item is at first undefined, then when it is assigned the value of a[i++] wouldn't the iteration start from i=1, which would mean that the iteration would start from the second element in the a[] array -> a[1], skipping over the first element a[0] entirely?
回答1:
i++
is the post increment operator, which means that it increments i
by 1
but evaluates to the old (non-incremented) value.
> i = 0
0
> i++
0
> i
1
回答2:
i++ is post increment (see other answers) and item will not be undefined, because the predicate (the second part in the for loop) is executed before each iteration.
for (var i = 0, item ; item = a[i++];) {
will evaluate to:
var i = 0;
var item;
item = a[i]; // loop
i += 1
if (!item) // exit loop
// loop body
// start again at loop
The problem with this syntax is, that if a value in a
is falsy, the loop will terminate prematurely.
var a = [1,2,0,3,4];
for (var i = 0, item ; item = a[i++];) {
console.log(item);
}
Will output "1 2" because "0" is falsy and the loop terminates
回答3:
i++ means that javascript reads the i value and then increments it
来源:https://stackoverflow.com/questions/16526670/javascript-array-iteration-mdn-example