PHP: Unable to get the json output into my javascript page as a variable value [duplicate]

问题

i have to get output in this format var sampleTags = ['c++', 'scala'];

My javascript function is:

 <script>
            $(document).ready(function(){
        $(function(){  
             var sampleTags;

            $.ajax({
                url:"<?php echo base_url('ajax_get_tags/gettags'); ?>"
            }).done(function(data) {
                if (data) {
                   sampleTags = data;
                }
            });
       ......................
        .......................



 $(function(){  
     var sampleTags = <?php echo json_encode($query) ?>;

My php controller is

   function gettags(){
    $json_array=$this->tagsmodel->get_all_tags(); 
   echo json_encode($json_array); 
 }

My model is

 //-------------------------------Function get all tags--------------------------------
function get_all_tags() { 
    $this->load->database();
    $this->db->limit('10');
    $this->db->select('tags_name');
    $res = $this->db->get('tags');
    $ret = array();

    foreach ($res->result_array() as $row) {
          $ret[] = $row['tags_name'];
    }

    return $ret;
}

How can get the json output from ajax request to be display its value for a javascript variable? Please help me to solve this issue..

回答1:

You're using an older version of jQuery, so .done won't work. It looks like you want to add a key to your request object called complete, with the anonymous function as its value:

$.ajax({
  url: "<?php echo base_url('ajax_get_tags/gettags'); ?>",
  complete: function(data) {
      if (data) {
          sampleTags = data;
      }
  }
});

I found this out by googling your error message. One of the results was this question: Object #<XMLHttpRequest> has no method 'done'. You could have just googled the error message and figured this out yourself.