How to get data from last 48 hours - Django

问题

I'm building a news website.I need display 48 hours most viewed news. So I need first to get the 48 hours news, and then get its pv. Currently I'm using a very complicated method which is from a tutorial:

def get_two_days_read_data(content_type):
    today = timezone.now().date()
    dates = []
    read_nums = []

    for i in range(2, 0, -1):
        date = today - datetime.timedelta(days=i)
        dates.append(date.strftime('%m/%d'))
        read_details = ReadDetail.objects.filter(content_type=content_type, date=date)
        result = read_details.aggregate(read_num_sum=Sum('read_num'))
        read_nums.append(result['read_num_sum'] or 0)
    return dates, read_nums

My question is, is there any easier way?

For example something like this:

def newsDetailView(request, news_pk):
    news = get_object_or_404(News, id=news_pk)
    News.objects.filter(id=news_pk).update(pv=F('pv') + 1)
    48_hours_hot_news = news.objects.filter(**48_housrs**).order_by('-pv')

    return render(request, "news_detail.html", {
        'news': news,
        '48_hours_hot_news' : 48_hours_hot_news
    })

Any friends can help?Thank you so much!

回答1:

You can do it with filter, your substract 48 hours from his date created, in case its result is greater than 48 hours or equal, you got recent news

from datetime import datetime, timedelta

thetime = datetime.now() - timedelta(hours=48)
results = news.objects.filter(date_created__gte=thetime)

Note a variable name can't be started with digit : 48_hours_hot_news : WRONG

来源：https://stackoverflow.com/questions/50418200/how-to-get-data-from-last-48-hours-django