问题
The website I want to scrap is :
http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061
I want to get the last page number of the above the link for proceeding, which is 499 while taking the screenshot.
My code :
from bs4 import BeautifulSoup
from urllib.request import urlopen as uReq
from selenium import webdriver;import time
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
firefox_capabilities = DesiredCapabilities.FIREFOX
firefox_capabilities['marionette'] = True
firefox_capabilities['binary'] = '/etc/firefox'
driver = webdriver.Firefox(capabilities=firefox_capabilities)
url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"
driver.get(url)
wait = WebDriverWait(driver, 10)
soup=BeautifulSoup(driver.page_source,"lxml")
containers = soup.findAll("ul",{"class":"pages table"})
containers[0] = soup.findAll("li")
li_len = len(containers[0])
for item in soup.find("ul",{"class":"pages table"}) :
li_text = item.select("li")[li_len].text
print("li_text : {}\n".format(li_text))
driver.quit()
I need help to figure out the error in my code for getting the last page number. Also, I would be grateful if someone give the alternate solution for the same and suggest ways to achieve my intention.
回答1:
If you want to get the last page number of the above the link for proceeding, which is 499
you can use either Selenium
or Beautifulsoup
as follows :
Selenium :
from selenium import webdriver
driver = webdriver.Firefox(executable_path=r'C:\Utility\BrowserDrivers\geckodriver.exe')
url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"
driver.get(url)
element = driver.find_element_by_xpath("//div[@class='row pagination']//p/span[contains(.,'Reviews on Reliance Jio')]")
driver.execute_script("return arguments[0].scrollIntoView(true);", element)
print(driver.find_element_by_xpath("//ul[@class='pagination table']/li/ul[@class='pages table']//li[last()]/a").get_attribute("innerHTML"))
driver.quit()
Console Output :
499
Beautifulsoup :
import bs4
from bs4 import BeautifulSoup as soup
from urllib.request import urlopen as uReq
url = "http://www.mouthshut.com/mobile-operators/Reliance-Jio-reviews-925812061"
uClient = uReq(url)
page_html = uClient.read()
uClient.close()
page_soup = soup(page_html, "html.parser")
container = page_soup.find("ul",{"class":"pages table"})
all_li = container.findAll("li")
last_div = None
for last_div in all_li:pass
if last_div:
content = last_div.getText()
print(content)
Console Output :
499
来源:https://stackoverflow.com/questions/47869382/scraping-contents-of-multi-web-pages-of-a-website-using-beautifulsoup-and-seleni