问题
In Python, I receive two floats e.g.
a = 0.123456
b = 0.012340
and a precision
p = 0.000001
that tells me there will be no digits beyond the 6th decimal of the floats. I want to transform the floats to two integers, so that every information they carry is represented in the integers.
int_a = 137632
int_b = 12340
The solution in this case is obviously to multiply them by 1000000, but I can't figure out a smart way to get there. I tried the workaround to get the number of digits in p by:
len(str(p))-1 //-1 because of the dot.
But:
>>> str(p)
>>> 1e-06
Well I could replace the "-" by a "+" in the string and transform it back to a float, but this seems for me to be a pretty ugly approach and I thought there must be a much cleaner, mathematical way to do that. Any suggestion?
回答1:
Why you just do not multiply a and b with 1/p ?
int(a * 1/p)
int(b * 1/p)
You exactly do not need python (or its string methods) other than converting resulting floats to integer, just arithmetics -))
来源：https://stackoverflow.com/questions/48815210/transform-float-to-int-so-that-every-information-is-preserved-or-how-to-get-the