Error while Iterating through a list

跟風遠走 提交于 2019-12-24 12:09:39

问题


[{'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}]

Thats my dict.

My code to make a list of values of dict_month

dict_month = []    
jan_month= []
for x in file_st:
    a=calendar.month_name[int(x['Start Time'][5:7])] #month name
    b=parser.parse(x['Start Time']).strftime("%a")  # day name
    dict_month.append({a:b})     # [{}]

for x in dict_month:
    jan_month.append(x['January'])

The error i get is

    KeyError                                  Traceback (most recent call 
last)
<ipython-input-42-879788f99587> in <module>()
 23 
 24 for x in dict_month:
---> 25     jan_month.append(x['January'])
     26 

 KeyError: 'January'

Where is the code wrong? how do i correct it?

output [sun,sun,sun]

edit its a key error this should help.


回答1:


Hope it may help you:

dict_month = [{'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}]  

jan_month =  [x['January'] for x in dict_month]

>>>['Sun', 'Sun', 'Sun', 'Sun']



回答2:


dict_month is a list of dicts and values can be append in a new list which is jan_month.

>>> dict_month = [{'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}]
>>> jan_month = []
>>> for x in dict_month:
...     jan_month.append(x['January'])
...
>>> jan_month
['Sun', 'Sun', 'Sun', 'Sun']



回答3:


[{'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}]

Is not a dict

a dict is something that is enclosed in {}

 {'January': 'Sun', 'January': 'Sun','January': 'Sun','January': 'Sun'}

Should be your dict

Anything enclosed in a [] is a list

So technically

[{'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}]

is a list, and each item of the list is a dict with 1 key,value pair

x = [{'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}]

xyz = []

for y in x:
     xyz.append(y['January'])

print(xyz)


来源:https://stackoverflow.com/questions/49186968/error-while-iterating-through-a-list

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