问题
Hi guys I have this code and I am not sure what I am doing wrong, data is being defined as far as I can see, these are the errors I am getting:
A PHP Error was encountered
Severity: Notice
Message: Undefined variable: data
Filename: models/site_model.php
Line Number: 14
A PHP Error was encountered
Severity: Warning
Message: Cannot modify header information - headers already sent by (output started at /Applications/XAMPP/xamppfiles/htdocs/BLOCK/system/core/Exceptions.php:185)
Filename: core/Common.php
Line Number: 442
A Database Error Occurred
You must use the "set" method to update an entry.
Filename: /Applications/XAMPP/xamppfiles/htdocs/BLOCK/models/site_model.php
Line Number: 14
controller:
<?php
class Site extends CI_Controller {
function index(){
$this->load->view('option_view');
}
function create(){
$data = array(
'subject' => $this->input->post('subject'),
'body' => $this->input->post('body')
);
$this->Site_model->add_record($data);
$this->index();
}
}
?>
model:
<?php
class Site_model extends CI_Model {
function get_records()
{
$query = $this->db->get('items');
return $query->result();
}
function add_record()
{
$this->db->insert('items', $data);
$return;
}
function update_record()
{
$this->db->where('id', 1);
$this->db->update('items', $data);
}
function delete_record()
{
$this->db->where('id', $this->url->segment(3));
$this->db->delete('items');
}
}
?>
and the view:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title>option_view</title>
<style type="text/css" media="screen">
label {display:block;}
</style>
</head>
<body>
<h2>Create</h2>
<?php echo form_open('site/create'); ?>
<p>
</label for="subject">Subject</label>
<input type="text" name="subject" id="subject">
</p>
<p>
</label for="body">Body</label>
<input type="text" name="body" id="body">
</p>
<p>
<input type="submit" value="Submit">
</p>
<?php echo form_close();?>
</body>
</html>
What do you guys reckon?
Much appreciated
回答1:
The method in your models aren't expecting a parameter. For example:
Change:
function add_record()
to:
function add_record($data)
回答2:
You never pass $data
to your methods. This is a scope issue.
function add_record()
{
$this->db->insert('items', $data);
$return;
}
In this case, add_record()
has no idea what $data
is (and treats it as null
because it hasn't been defined.
Variable Scope
回答3:
In these methods:
function add_record()
{
$this->db->insert('items', $data);
$return;
}
function update_record()
{
$this->db->where('id', 1);
$this->db->update('items', $data);
}
You have not passed data to the methods, so $data is undefined.
来源:https://stackoverflow.com/questions/11748324/message-undefined-variable-data-codeigniter