问题
I know I can generate a class at runtime by executing
$obj = (object)array('foo' => 'bar');+
this way I can use
echo $obj->foo; //bar
What if want to make $obj inherits from an existing class?
What I wanna achive: I'm forking paris project on github (https://github.com/balanza/paris). It's an active record class. I wonder I need to declare a class for every object, even if it's empty:
class User extends Model{}
I guess I might use dynamic object to avoid this boring stuff.
回答1:
You could always do eval('class User extends Model{}') but is not a good idea. Really, you should just create the class in a file, then opcode caching will work properly, it can be version tracked, etc etc.
tl;dr: Define the model class, it is the Right Thing To Do™.
回答2:
If there is really no other way for you to do it, you can create a "dynamic" inheritance with my Dynherit class. It creates the inheritance you want but from files and only with classes you didnt already loaded.
Download v0.62 : http://optimisationphp.komrod.com/source/sha/test/dynamic_inheritance_01/dynherit_v0.62.zip
GitHub link : https://github.com/Komrod/Dynherit
回答3:
Strictly to your question, the only way I can see it possible is by using Runkit, which let's you re-declare classes on the fly. Not sure how portable that solution is.
来源：https://stackoverflow.com/questions/4924616/php-dynamic-class-inheritance