How to effectively convert a POSIX path to Windows path with Python in Cygwin?

问题

Problem

Imagine you are writing a Python script which runs on cygwin and calls an external C# executable which requires as input a path. Assume you cannot change the C# executable in any way. As you send the path you want to the executable, it rejects all cygwin paths.

So if you pass the path /cygdrive/c/location/of/file.html as a POSIX path, it will fail as the executable requires a Windows path like C:\location\of\file.html

Example:

Message location = os.path.dirname(os.path.realpath(__file__)) os.system('./cSharpScript.exe ' + message_location)

Will result in:

File for the content (/cygdrive/c/location/of/file.html) not found.

Things I've tried so far:

PATH = /cygdrive/c/location/of/file.html

1) path = PATH.replace('/','\\')

Result: File for the content (cygdriveclocationoffile.html) not found.

2) path = os.path.abspath(PATH)

Result: File for the content (/cygdrive/c/location/of/file.html) not found.

• os.path.realpath has the same results

I'm probably going in a completely wrong direction with my solutions so far... How would you handle it?

回答1:

According to [Cygwin]: cygpath:

cygpath - Convert Unix and Windows format paths, or output system path information
...

-w, --windows         print Windows form of NAMEs (C:\WINNT)

Example:

[cfati@cfati-5510-0:/cygdrive/e/Work/Dev/StackOverflow/q054237800]> cygpath.exe -w /cygdrive/c/location/of/file.html
C:\location\of\file.html

Translated into Python (this is a rough version, only for demonstrating purposes):

>>> import subprocess
>>>
>>>
>>> def get_win_path(cyg_path):
...     return subprocess.check_output(["cygpath", "-w", cyg_path]).strip(b"\n").decode()
...
>>>
>>> print(get_win_path("/cygdrive/c/location/of/file.html"))
C:\location\of\file.html

来源：https://stackoverflow.com/questions/54237800/how-to-effectively-convert-a-posix-path-to-windows-path-with-python-in-cygwin