问题
It seems like scala.collection.SortedMap is not serializable?
Simple code example:
case class MyClass(s: scala.collection.SortedMap[String, String] = SortedMap[String, String]())
object MyClass {
def apply(i: Int): MyClass = MyClass()
}
import sparkSession.implicits._
List(MyClass(1), MyClass()).toDS().show(2)
Will return:
+-----+
| s|
+-----+
|Map()|
|Map()|
+-----+
On the other hand, take() will fail miserably at execution time:
List(MyClass(1), MyClass()).toDS().take(2)
ERROR codegen.CodeGenerator: failed to compile: org.codehaus.commons.compiler.CompileException: File 'generated.java', Line 116, Column 100: No applicable constructor/method found for actual parameters "scala.collection.Map"; candidates are: "com.caspida.algorithms.security.offline.exfiltrationthreat.MyClass(scala.collection.SortedMap)"
回答1:
The supported Scala types for Spark (as of 2.1.0) do not include scala.collection.SortedMap). A list of supported types can be found here:
https://spark.apache.org/docs/latest/sql-programming-guide.html#data-types
As the link suggest, the supported type for Maps is scala.collection.Map
so the following works:
case class MyClass(s: scala.collection.Map[String, String] = SortedMap[String, String]())
scala> spark.createDataset( MyClass() :: Nil ).collect()
res: Array[MyClass2] = Array(MyClass(Map()))
来源:https://stackoverflow.com/questions/42964531/sortedmap-non-serializable-error-in-spark-dataset