问题
I want to validate a string in javascript that contains a Boolean expression with brackets. The string should only contain numbers 1-9
, ()
, OR
, AND
.
Examples of good strings:
"1 AND 2"
"2 OR 4"
"4 AND (3 OR 5)"
I am not sure if Regular Expression are flexible enough for this task. Is there a nice short way of achieving this in javascript ?
回答1:
In JavaScript, you can use the following.
replace 'AND/OR/NOT' with '&&/||/!'.
use eval
to evaluate it.
Careful because eval is a powerful function
var string = "0 AND 2";
var string1 = "0 OR 2";
var string2 = "NOT 0";
evaluate(string);
evaluate(string1);
evaluate(string2);
function evaluate(string){
string=string.replace(/AND/g,'&&');
string=string.replace(/OR/g,'||');
string=string.replace(/NOT/g,'!');
console.log(eval(string));
}
回答2:
While regex alone isn't powerful enough for this task (because JS regex can't handle nested braces), it's an easy task with a little help from Javascript.
Since we can't deal with nested braces, we'll deal with the braces one at a time until none are left. The pattern \(\d\)|\d (?:AND|OR) \d|\d
will match an expression of the form (X)
or X AND/OR Y
or X
(where X
and Y
are digits). We replace all occurrences of this pattern with 1
(or any other valid expression in your boolean language), until the pattern no longer matches. If after all replacements are done the string is "1"
, then it was a valid expression.
function validate(expression){
const pattern = /\(\d\)|\d (?:AND|OR) \d|\d/g;
while (true){
const replaced = expression.replace(pattern, "1");
// if the expression has been reduced to "1", it's valid
if (replaced == "1") return true;
// if the pattern didn't match, it's invalid
if (replaced == expression) return false;
// otherwise, continue replacing
expression = replaced;
}
}
Note that the regex doesn't allow for extra spaces.
来源:https://stackoverflow.com/questions/42528748/validate-a-boolean-expression-with-brackets-in-javascript-regex