Type 'NSNotification.Name' has no member 'keyboardDidShowNotification'

Question

I'm getting this error with Swift 4.2

Type 'NSNotification.Name' has no member 'keyboardDidShowNotification'

Here is my code:

NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardDidShow(notification:)), name: NSNotification.Name.keyboardDidShowNotification, object: nil)

Following one was working fine with Swift 4 but not with Swift 4.2

NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardDidShow(notification:)), name: NSNotification.Name.UIKeyboardDidShow, object: nil)

Apple document Ref: NSNotification.Name.keyboardDidShowNotification

Answer 1

I believe you use it like this now.

NotificationCenter.default.addObserver(
    self, 
    selector: #selector(self.keyboardDidShow(notification:)), 
    name: UIResponder.keyboardDidShowNotification, object: nil) 

/* You can substitute UIResponder with any of it's subclass */

It is listed in UIResponder doc as a Type Property.

Answer 2

Working on swift 4,2

 func bindToKeyboard(){
    NotificationCenter.default.addObserver(self, selector: #selector(UIView.keyboardWillChange(_:)), name:
        UIApplication.keyboardWillChangeFrameNotification
        , object: nil)


}

Answer 3

I have used just the UIResponder.keyboardWillHideNotification except using NSNotification.Name. . This is working in SWIFT 5

NotificationCenter.default.addObserver(self, selector: #selector(KeyboardLayoutConstraint.keyboardWillShowNotification(_:)), name: UIResponder.keyboardWillShowNotification, object: nil)

NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardWillHideNotification(_:)), name: UIResponder.keyboardWillHideNotification, object: nil)