问题
Am working on Oracle 12c R1 db and have a sample view with sample data as below:
View Name: CUST_HOTEL_VIEW
+----------------+---------------+---------------+
| Customer | Hotel | Booked Status |
+----------------+---------------+---------------+
| John Smith | Beverly Hills | Booked |
| John Smith | Royal Palms | |
| Marilyn Lawson | Beverly Hills | |
| John Smith | Ritz-Carlton | |
| Marilyn Lawson | Royal Palms | |
| Sarah Elliot | Royal Palms | |
| Sarah Elliot | Ritz-Carlton | Booked |
| Sarah Elliot | Royal Palms | Booked |
+----------------+---------------+---------------+
From the data above, am trying to get below pivot output with Row Grand Total, Column Grand Total and Number of Hotels booked per customer:
+----------------+-------------+---------------+--------------+-------------+----------+
| Customer | Royal Palms | Beverly Hills | Ritz-Carlton | Grand Total | # Booked |
+----------------+-------------+---------------+--------------+-------------+----------+
| John Smith | 1 | 1 | 1 | 3 | 1 |
| Marilyn Lawson | 1 | 1 | | 2 | - |
| Sarah Elliot | 2 | | 1 | 3 | 2 |
| Grand Total | 4 | 2 | 2 | 8 | 3 |
+----------------+-------------+---------------+--------------+-------------+----------+
I tried below query to generate pivot data
SELECT * FROM
(
SELECT CUSTOMER, HOTEL
FROM CUST_HOTEL_VIEW
)
PIVOT
(
COUNT(HOTEL)
FOR HOTEL IN ('Royal Palms' as "Royal Palms",'Beverly Hills' as "Beverly Hills",'Ritz-Carlton' as "Ritz-Carlton")
)
ORDER BY CUSTOMER
I would like to know:
1. How to include Row Grand Total
2. How to include Column Grand Total
3. How to include Number of Booked hotels and
3. Is it possible to write subquery inside PIVOT FOR HOTEL IN clause. (I tried subquery but getting error)
I appreciate any help on this.
Thanks,
Richa
回答1:
Just use conditional aggregation:
SELECT COALESCE(customer, 'Grand Total') as customer,
SUM(CASE WHEN Hotel = 'Royal Palms' THEN 1 ELSE 0 END) as "Royal Palms",
SUM(CASE WHEN Hotel = 'Beverly Hills' THEN 1 ELSE 0 END) as "Beverly Hills",
SUM(CASE WHEN Hotel = 'Ritz-Carlton' THEN 1 ELSE 0 END) as "Ritz-Carlton" ,
COUNT(*) as "Grand Total",
COUNT(Booked_Status) as "Num Booked"
FROM CUST_HOTEL_VIEW
GROUP BY ROLLUP(CUSTOMER)
ORDER BY CUSTOMER;
Conditional aggregation is much more flexible then pivot. Personally, I see no reason for the pivot syntax: it does one thing well, but is not a building block the way tradition SQL statements are.
ROLLUP() is also quite helpful. You can also use:
GROUP BY GROUPING SETS ( (CUSTOMER), () )
回答2:
There might be an easier solution but this should help you get started -
WITH A AS (
SELECT
*
FROM
(
SELECT
CUSTOMER,
HOTEL,
BOOKED_STATUS
FROM
TABLE1
)
PIVOT ( COUNT ( HOTEL )
FOR HOTEL
IN ( 'ROYAL PALMS' AS "ROYAL PALMS",'BEVERLY HILLS' AS "BEVERLY HILLS",'RITZ-CARLTON' AS "RITZ-CARLTON" )
)
),B AS (
SELECT
CUSTOMER,
"ROYAL PALMS",
"BEVERLY HILLS",
"RITZ-CARLTON",
SUM("ROYAL PALMS" + "BEVERLY HILLS" + "RITZ-CARLTON") AS "GRAND TOTAL"
FROM
A
GROUP BY
CUSTOMER,
"ROYAL PALMS",
"BEVERLY HILLS",
"RITZ-CARLTON"
),C AS (
SELECT
CUSTOMER,
SUM("ROYAL PALMS" + "BEVERLY HILLS" + "RITZ-CARLTON") AS NBOOK
FROM
A
WHERE
BOOKED_STATUS IS NOT NULL
GROUP BY
CUSTOMER
),D AS (
SELECT
B.CUSTOMER,
SUM("ROYAL PALMS") AS "ROYAL PALMS",
SUM("BEVERLY HILLS") AS "BEVERLY HILLS",
SUM("RITZ-CARLTON") AS "RITZ-CARLTON",
SUM("GRAND TOTAL") AS "GRAND TOTAL",
NVL(C.NBOOK,0) AS NBOOK
FROM
B,
C
WHERE
B.CUSTOMER = C.CUSTOMER (+)
GROUP BY
B.CUSTOMER,
NVL(C.NBOOK,0)
) SELECT
*
FROM
D
UNION
SELECT
'GRAND TOTAL' AS CUSTOMER,
SUM("ROYAL PALMS"),
SUM("BEVERLY HILLS"),
SUM("RITZ-CARLTON"),
SUM("GRAND TOTAL") AS "GRAND TOTAL",
SUM(NBOOK) AS NBOOK
FROM
D
ORDER BY 5,1;
Output -
"CUSTOMER","ROYAL PALMS","BEVERLY HILLS","RITZ-CARLTON","GRAND TOTAL","NBOOK"
"MARILYN LAWSON",1,1,0,2,0
"JOHN SMITH",1,1,1,3,1
"SARAH ELLIOT",2,0,1,3,2
"GRAND TOTAL",4,2,2,8,3
回答3:
Try this out:
1) To include row total union can be used
2) To include column total sum function is used in the first table (p1) : the same code written by you with the sum function
3) To include number of booked hotels, another pivot is required, which is second table (p2)
Step1: Made a table p1 with customer,different hotels, and their grand total (column total)
create table p1 as
SELECT customer,RoyalPalms,BeverlyHills,RitzCarlton,sum(RoyalPalms + BeverlyHills + RitzCarlton) as GrandTotal FROM
(
SELECT CUSTOMER, HOTEL
FROM CUST
)
PIVOT
( COUNT(HOTEL)
FOR HOTEL IN ('Royal Palms' as RoyalPalms,'Beverly Hills' as BeverlyHills,
'Ritz-Carlton' as RitzCarlton) )
group by customer,RoyalPalms,BeverlyHills,RitzCarlton
order by customer;
Step2: Make a table p2 with customer and booked hotels
create table p2 as
SELECT * FROM
(
SELECT customer,booked_status
FROM cust
)
pivot
( count(booked_status)
for booked_status in ('Booked' as Booked));
Step3: Join table p1 and p2
Step4: For row total, take the union of table made in Step3 with the row totals calculated by summary function
(SELECT a.*,b.booked
from p1 a
left join
p2 b
on a.customer = b.customer)
union all
SELECT 'GrandTotal', Sum(RoyalPalms),sum(BeverlyHills),sum(RitzCarlton),
sum(GrandTotal),sum(booked) From test;
Output:
+----------------+-------------+---------------+--------------+-------------+----------+
| Customer | Royal Palms | Beverly Hills | Ritz-Carlton | Grand Total | # Booked |
+----------------+-------------+---------------+--------------+-------------+----------+
| John Smith | 1 | 1 | 1 | 3 | 1 |
| Marilyn Lawson | 1 | 1 | | 2 | - |
| Sarah Elliot | 2 | | 1 | 3 | 2 |
| Grand Total | 4 | 2 | 2 | 8 | 3 |
+----------------+-------------+---------------+--------------+-------------+----------+
Let me know in case of any further queries/explanation required.
来源：https://stackoverflow.com/questions/50537526/oracle-sql-pivot-table-rows-to-column-and-use-sub-query-in-pivot