问题
I'm trying http requests and create http get request to server. Server must return .zip file. here is the code:
url = new URL(urlToRead);
conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
is = conn.getInputStream();
then I want to write it to file like this:
r = 1;
while(r > 0){
r = is.read(buf);
if(r > 0)
fos.write(buf, 0, r);
}
but to create fileoutputstream i want to use the file name provided by server. I've found that server answer has the file name and all the structure looks like this:
HTTP/1.1 200 OK
Date: Mon, 07 Apr 2003 14:51:19 GMT
Server: Apache/1.3.20 (Win32) PHP/4.3.0
Last-Modified: Mon, 07 Apr 2003 14:51:00 GMT
Accept-Ranges: bytes
Content-Length: 673
Keep-Alive: timeout=15, max=100
Connection: Keep-Alive
Content-Type: application/zip
Content-Disposition: attachment; filename=test.zip
Pragma: no-cache
....(zip content)
how to get filename?
回答1:
You can use the HttpUrlConnection
object's getHeaderField()
method to read the Content-Disposition header. Also make sure you handle the case when it is not present.
回答2:
Have you had a look at the methods that HttpURLConnection offers?
Especially the ones that involve headers
?
回答3:
if u have servletRequest object(lets say obj) then i think this will help
obj.getRequestURL() ;
来源:https://stackoverflow.com/questions/29622396/how-to-get-file-name-from-the-server-request