Equivalent to InnerHTML when using lxml.html to parse HTML

故事扮演 提交于 2019-11-27 08:51:37

You can get the children of an ElementTree node using the getchildren() or iterdescendants() methods of the root node:

>>> from lxml import etree
>>> from cStringIO import StringIO
>>> t = etree.parse(StringIO("""<body>
... <h1>A title</h1>
... <p>Some text</p>
... </body>"""))
>>> root = t.getroot()
>>> for child in root.iterdescendants(),:
...  print etree.tostring(child)
...
<h1>A title</h1>

<p>Some text</p>

This can be shorthanded as follows:

print ''.join([etree.tostring(child) for child in root.iterdescendants()])

Sorry for bringing this up again, but I've been looking for a solution and yours contains a bug:

<body>This text is ignored
<h1>Title</h1><p>Some text</p></body>

Text directly under the root element is ignored. I ended up doing this:

(body.text or '') +\
''.join([html.tostring(child) for child in body.iterchildren()])
import lxml.etree as ET

     body = t.xpath("//body");
     for tag in body:
         h = html.fromstring( ET.tostring(tag[0]) ).xpath("//h1");
         p = html.fromstring(  ET.tostring(tag[1]) ).xpath("//p");             
         htext = h[0].text_content();
         ptext = h[0].text_content();

you can also use .get('href') for a tag and .attrib for attribute ,

here tag no is hardcoded but you can also do this dynamic

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