问题
I have the below code for creating threads and running them.
from concurrent.futures import ThreadPoolExecutor
import threading
def task(n):
result = 0
i = 0
for i in range(n):
result = result + i
print("I: {}".format(result))
print(f'Thread : {threading.current_thread()} executed with variable {n}')
def main():
executor = ThreadPoolExecutor(max_workers=3)
task1 = executor.submit(task, (10))
task2 = executor.submit(task, (100))
if __name__ == '__main__':
main()
When i run the code in my windows 10 machine this is the output which gets generated:
I: 45
Thread : <Thread(ThreadPoolExecutor-0_0, started daemon 11956)> executed with variable 10
I: 4950
Thread : <Thread(ThreadPoolExecutor-0_0, started daemon 11956)> executed with variable 100
Process finished with exit code 0
As we see both the threads have the same name. How do i differentiate between them by giving them different names ? Is this somehow a feature of the concurrent.futures class ?
Many thanks for any answers.
回答1:
from the docs:
New in version 3.6: The thread_name_prefix argument was added to allow users to control the threading.Thread names for worker threads created by the pool for easier debugging.
来源：https://stackoverflow.com/questions/51439283/how-to-give-different-names-to-threadpoolexecutor-threads-in-python