问题
so i'm a bit struggling with Lists in Netlogo, so basically i've two lists and i want to remove the items that are in List 1 from List 2, for example:
List 1 : [8 6 9 7 1 3]
List 2: [5 9 8]
Resulting List : [6 7 1 3]
I've tried the following code but it returns an empty list:
if List 2 != []
[
foreach List 2
[
let p position ? List 1
if p = true
[
set List 1 remove-item p List 1
]
]
]
Any ideas ?
回答1:
A combination of member? and filter will get you there:
let list1 [8 6 9 7 1 3]
let list2 [5 9 8]
let result filter [ x -> not member? x list2 ] list1
print result
Will print the desired:
[6 7 1 3]
Tip: whenever you find yourself trying to use an index for anything in NetLogo, you are probably not doing things in the optimal way. NetLogo has tons of functions (like filter
, in this case) that operate on lists as a whole. There is rarely a need to explicitly loop through them.
来源:https://stackoverflow.com/questions/49379498/how-to-remove-several-items-from-a-unsorted-list-in-netlogo