问题
I want to find out if a string ends with number (with/without decimal). If it ends, I want to extracts it.
"Test1" => 1
"Test" => NOT FOUND
"Test123" => 123
"Test1.1" => 1.1
I have missed a few details.
1. Prior to number, string can contain special characters also
2. It is single line, not multiline.
回答1:
give this pattern a try,
\d+(\.\d+)?$
回答2:
Matches line start, any chars after that and a a number (with optional decimal part) at the end of the string (allowing trailing whitespace characters). The fist part is a lazy match, i.e. it will match the lowest number of chars possible leaving the whole number to the last part of the expression.
^.*?(\d+(?:[.,]\d+)?)\s*$
My test cases
"Test1
"Test
"Test123
"Test1.1
test 1.2 times 1 is 1.2
test 1.2 times 1 is ?
test 1.2 times 1 is 134.2234
1.2
回答3:
Use the following regex in c# (\d+)$
回答4:
A regex for a string that ends with a number: @"\d$". Use http://regexpal.com/ to try out regexes.
Of course, that just tells you that the last character is a number. It doesn't capture anything other than the last character. To capture the number only this is needed: @"\d*\.?\d+$".
If your string can be more complicated, eg "Test1.2 Test2", and you want both numbers: @"\d*\.?\d+\b".
回答5:
use this regex [a-zA-Z]+\d+([,.]\d+)?\b$
if you want digit only use this one (?<=[a-zA-Z]+)\d+([,.]\d+)?\b$
来源：https://stackoverflow.com/questions/14294154/regex-for-number-at-the-end-of-string