Python 3.X Unix Socket Example [duplicate]

问题

I have been searching the last couple of hours on finding a simple Server / Client Unix Socket Example. I have found examples for Python 2.X, but I am failing at finding one that works for Python 3.X.

I keep getting TypeErrors.

The example that I have been working with is:

client.py

# -*- coding: utf-8 -*-
import socket
import os
# import os, os.path

print("Connecting...")
if os.path.exists("/tmp/python_unix_sockets_example"):
    client = socket.socket( socket.AF_UNIX, socket.SOCK_DGRAM )
    client.connect("/tmp/python_unix_sockets_example")
    print("Ready.")
    print("Ctrl-C to quit.")
    print("Sending 'DONE' shuts down the server and quits.")
    while True:
#        try:
            x = input( "> " )
            if "" != x:
            print("SEND:", x)
                client.send( x )
                if "DONE" == x:
                    print("Shutting down.")
                break
#        except KeyboardInterrupt, k:
#            print("Shutting down.")
    client.close()
else:
    print("Couldn't Connect!")
    print("Done")

With the client portion, I was not sure how to get a KeyboardInterupt to work in 3.X, so I killed the Try and Except portions. Any Advice?
Also, the syntax from the example I used had multiple modules being loaded from one import import os, os.path Is this the old way of only loading os.path from os module?

server.py

# -*- coding: utf-8 -*-

import socket
import os
# import os, os.path
# import time

if os.path.exists("/tmp/python_unix_sockets_example"):
    os.remove("/tmp/python_unix_sockets_example")

print("Opening socket...")
server = socket.socket(socket.AF_UNIX, socket.SOCK_DGRAM)
server.bind("/tmp/python_unix_sockets_example")

print("Listening...")
while True:
    datagram = server.recv(1024)

    if not datagram:
        break
    else:
        print("-" * 20)
        print(datagram)
        if "DONE" == datagram:
            break
print("-" * 20)
print("Shutting down...")
server.close()
os.remove("/tmp/python_unix_sockets_example")
print("Done")

When I run this I get TypeError: 'str' does not support the buffer interface.
Does Python 3.4 Unix Sockets only support binary?
What is the easiest way to make this work?

Thanks in advance!

回答1:

To answer the OP's questions explicitly:

The "TypeError: 'str' does not support the buffer interface" error was caused by attempting to send/receive string-encoded data over a bytes interface.
Unix sockets have no knowledge of encodings, they pass raw bytes, and Python 3+ no longer does any magic bytes<->encoded string conversions for you, so in this sense yes, (Python 3(.4)) Unix sockets only support "binary".
The easiest way to make it work was as @jmhobbs demonstrated in his above-linked gist: you must .encode() your strings to bytes when client.send()'ing them and .decode() the bytes back to strings when server.recv()'ing them.

回答2:

One thing you may need to do is replace if os.path.exists("/tmp/python_unix_sockets_example"): with if os.path.exists("/tmp/python_unix_sockets_example") == True:

来源：https://stackoverflow.com/questions/23282635/python-3-x-unix-socket-example

标签

python-3.4