问题
I have to get the datatype and do a case match and convert it to some required format. But the usage of org.apache.spark.ml.linalg.VectorUDT
is showing VectorUDT
is private
. Also I specifically need to use org.apache.spark.ml.linalg.VectorUDT
and not org.apache.spark.mllib.linalg.VectorUDT
. Can someone suggest how to go about this?
回答1:
For org.apache.spark.ml.linalg
types you should specify schema using org.apache.spark.ml.linalg.SQLDataTypes
which provide singleton instances of the private UDT types:
MatrixType for matrices (
org.apache.spark.ml.linalg.Matrix
).scala> org.apache.spark.ml.linalg.SQLDataTypes.MatrixType.getClass res0: Class[_ <: org.apache.spark.sql.types.DataType] = class org.apache.spark.ml.linalg.MatrixUDT
VectorType for vectors (
org.apache.spark.ml.linalg.Vector
).scala> org.apache.spark.ml.linalg.SQLDataTypes.VectorType.getClass res1: Class[_ <: org.apache.spark.sql.types.DataType] = class org.apache.spark.ml.linalg.VectorUDT
来源:https://stackoverflow.com/questions/45809316/vectorudt-usage