How to slice middle element from list

问题

Rather simple question. Say I have a list like:

a = [3, 4, 54, 8, 96, 2]

Can I use slicing to leave out an element around the middle of the list to produce something like this?

a[some_slicing]
[3, 4, 8, 96, 2]

were the element 54 was left out. I would've guessed this would do the trick:

a[:2:]

but the result is not what I expected:

[3, 4]

回答1:

You cannot emulate pop with a single slice, since a slice only gives you a single start and end index.

You can, however, use two slices:

>>> a = [3, 4, 54, 8, 96, 2]
>>> a[:2] + a[3:]
[3, 4, 8, 96, 2]

You could wrap this into a function:

>>> def cutout(seq, idx):
        """
        Remove element at `idx` from `seq`.
        TODO: error checks.
        """
        return seq[:idx] + seq[idx + 1:]

>>> cutout([3, 4, 54, 8, 96, 2], 2)
[3, 4, 8, 96, 2]

However, pop will be faster. The list pop function is defined in listobject.c.

回答2:

To remove an item in-place call:

your_list.pop(index)

It will return the removed item and change your_list.

回答3:

Slice the two parts separately and add those lists

a[:2] + a[3:]

回答4:

To work on any size list:

a.pop((len(a)-1)//2)

回答5:

It is the easiest answer:

>>>a = [3, 4, 54, 8, 96, 2]

>>>a.remove(54)

[3, 4, 8, 96, 2]

来源：https://stackoverflow.com/questions/30757538/how-to-slice-middle-element-from-list