问题
I have a query something like this:
SELECT
title, desc, date
FROM
tablename
ORDER BY
date ASC, title ASC;
Works fine when the data actually has a date. Issue is, date submission is optional, so I sometimes get 0000-00-00 as a date, which has the unfortunate effect of placing all nondated rows on top.
So, I then tried this:
SELECT
title, desc, date
FROM
tablename
ORDER BY
date DESC, title ASC;
Which sort of works, but not really -- all items with dates (non 0000-00-00) get listed in descending order, followed by all items with 0000-00-00.
What I want to do is order by date ASC, title ASC, but only if the date != 0000-00-00, but if date is = 0000-00-00, then just ORDER BY title ASC on those (I think I explained that correctly).
The only ways I can think to do this are non-SQL based (either 2 queries, or, each query just populates an in-memory array, and then I sort using PHP).
Is there a SQL query that can do this?
回答1:
Your 2 query solution is a good one, you can do it all in SQL using the UNION command.
The first query will be for dates that are non-zero, then UNION in the query for dates that are zero.
Edit: Something like:
SELECT * FROM tbl
WHERE DATE != '0000-00-00'
ORDER BY date ASC
UNION SELECT * FROM tbl
WHERE DATE = '0000-00-00'
ORDER BY title ASC
This may not be very useful in this instance, but for complex queries, UNION
can come in handy.
回答2:
ORDER BY date = '0000-00-00' ASC, date ASC, title ASC
来源:https://stackoverflow.com/questions/880430/mysql-order-by-using-date-data-row