How does slideUp() work in jQuery? I'm trying to make my own slideRIght()

问题

I have looked at the source code in jquery for slideup...

// Generate shortcuts for custom animations
jQuery.each({
    slideDown: genFx("show", 1),
    slideUp: genFx("hide", 1),
    slideToggle: genFx("toggle", 1),
    fadeIn: { opacity: "show" },
    fadeOut: { opacity: "hide" },
    fadeToggle: { opacity: "toggle" }
}, function( name, props ) {
    jQuery.fn[ name ] = function( speed, easing, callback ) {
        return this.animate( props, speed, easing, callback );
    };
});

I understand that this is shorthand for functions, so I folllow through to GenFX

function genFx( type, num ) {
    var obj = {};

    jQuery.each( fxAttrs.concat.apply([], fxAttrs.slice(0,num)), function() {
        obj[ this ] = type;
    });

    return obj;
}

and then fxAttrs

fxAttrs = [
        // height animations
        [ "height", "marginTop", "marginBottom", "paddingTop", "paddingBottom" ],
        // width animations
        [ "width", "marginLeft", "marginRight", "paddingLeft", "paddingRight" ],
        // opacity animations
        [ "opacity" ]
    ],

but I just can't figure out how this code works, or how I would go about creating a slideLeft or slideRight that affects the width attribute of the HTML.

回答1:

You can use:

$('div').animate({ width: 'show' }); // slideLeft

$('div').animate({ width: 'hide' }); // slideRight

Demo at jsFiddle.

回答2:

You can do the same with slideRight as with slideUp:

$.fn.slideRight = function(options) {
    var s_opt = {
        speed: "slow",
        callback: null
    }

    $.extend(s_opt, options);
   return this.each(function() {
        $(this).effect("slide", null,
            s_opt.speed, s_opt.callback);
   });
};

Fiddle: http://jsfiddle.net/maniator/eVUsH/

来源：https://stackoverflow.com/questions/6154353/how-does-slideup-work-in-jquery-im-trying-to-make-my-own-slideright

标签

jquery

jquery-animate