Linux bash script for loop

问题

i have 1.txt 2.txt and script.php

1.txt:
a
b
c
d
2.txt
www
rrr
ttt
yyy

i want bash file to do this command in Linux:

./script.php -n a -j www>>n_j.txt
./script.php -n a -j rrr>>n_j.txt
./script.php -n a -j ttt>>n_j.txt
./script.php -n a -j yyy>>n_j.txt
./script.php -n b -j www>>n_j.txt
./script.php -n b -j rrr>>n_j.txt
./script.php -n b -j ttt>>n_j.txt
.
.

i have a bat code working with wondows cmd..i wanna a code like it to work with Linux command line

@ECHO OFF


FOR /F "tokens=1 delims= " %%I IN (1.txt) DO FOR /F "tokens=1 delims= " %%E IN (2.txt) DO echo %%I %%E>n_j.txt & echo name_job: %%I %%E & FOR /F "tokens=*" %%S IN ('script.php -n %%I -j %%E') DO echo %%S>>names\n_j.txt

回答1:

#!/bin/bash

arr1=""
arr2=""
mapfile -t arr1 <1.txt
mapfile -t arr2 <2.txt

for i in ${!arr1[@]}; do
        for j in ${!arr2[@]}; do
                ./script.php -n "${arr1[i]}" -j "${arr2[j]}" >>n_j.txt
        done
done

mapfile -t converts the file to an array, where each line of the file is a new index in the array (-t removes the trailing newline). The for loops iterate over each index of the array, the outer loop going through the lines in the first file, the inner loop going through the lines in the second file, calling script.php with the current array indices.

回答2:

Simply pipe the file in while loop, see if this could help.

#!/bin/bash
while read arg1
do
   while read arg2
   do
     ./script.php -n $arg1 -j $arg2 >>n_j.txt
   done<2.txt
done<1.txt

来源：https://stackoverflow.com/questions/35713640/linux-bash-script-for-loop

标签

Linux

bash

batch-file