问题
in my app i implemented push notification. when my app is in running state and if push notification come i am handle that with this code.
func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject]) {
print(userInfo)
myid = (userInfo["id"] as? String)!
print(myid)
if let notification = userInfo["aps"] as? NSDictionary,
let alert = notification["alert"] as? String {
var alertCtrl = UIAlertController(title: "Notification", message: alert as String, preferredStyle: UIAlertControllerStyle.Alert)
alertCtrl.addAction(UIAlertAction(title: "OK", style: UIAlertActionStyle.Default, handler: nil))
// Find the presented VC...
var presentedVC = self.window?.rootViewController
while (presentedVC!.presentedViewController != nil) {
presentedVC = presentedVC!.presentedViewController
}
presentedVC!.presentViewController(alertCtrl, animated: true, completion: nil)
}
What i want :: when my app is not running and if push notification come i want to open perticular post based on that notification post id. so how can i do this? Here is my code
func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
SVProgressHUD.setDefaultMaskType(SVProgressHUDMaskType.Black)
UIApplication.sharedApplication().applicationIconBadgeNumber = 0
let dicTemp = launchOptions?["UIApplicationLaunchOptionsRemoteNotificationKey"]
if dicTemp != nil{
window = UIWindow(frame: UIScreen.mainScreen().bounds)
storyboard = UIStoryboard(name: "Main", bundle: nil)
myid = (dicTemp["id"] as? String)!
let controller:pushnotificationpostViewController = self.storyboard.instantiateViewControllerWithIdentifier("pushnotificationpostViewController") as! pushnotificationpostViewController
navigation = UINavigationController(rootViewController: controller)
window?.rootViewController = navigation
window?.makeKeyAndVisible()
}
else
{
window = UIWindow(frame: UIScreen.mainScreen().bounds)
storyboard = UIStoryboard(name: "Main", bundle: nil)
let controller:MainViewController = self.storyboard.instantiateViewControllerWithIdentifier("MainViewController") as! MainViewController
navigation = UINavigationController(rootViewController: controller)
window?.rootViewController = navigation
window?.makeKeyAndVisible()
}
//print(NSUserDefaults.standardUserDefaults().valueForKey("pushnotify")as! Bool)
let notificationTypes: UIUserNotificationType = [UIUserNotificationType.Alert, UIUserNotificationType.Badge, UIUserNotificationType.Sound]
let pushNotificationSettings = UIUserNotificationSettings(forTypes: notificationTypes, categories: nil)
application.registerUserNotificationSettings(pushNotificationSettings)
if (NSUserDefaults.standardUserDefaults().valueForKey("pushnotify")) != nil
{
pushnotification = NSUserDefaults.standardUserDefaults().valueForKey("pushnotify") as! Bool
// let notificationcheck = NSUserDefaults.standardUserDefaults().valueForKey("pushnotify") as! Bool
if (pushnotification == true)
{
application.registerForRemoteNotifications()
}
else
{
application.unregisterForRemoteNotifications()
}
}
else
{
application.registerForRemoteNotifications()
}
return true
}
but by this code i am not getting id means myid is getting nil. so how can i do this?
回答1:
i think when you quit your application the didReceiveRemoteNotification method not gets called when you tap on the notification, instead the method didFinishLaunchingWithOptions gets called there you have to check weather application is launched by notification
Put below code in your didFinishLaunchingWithOptions :
var notification: UILocalNotification = (launchOptions[UIApplicationLaunchOptionsRemoteNotificationKey] as! UILocalNotification)
if notification != nil {
// handle your notification
}
above code is for handling the push notifications if your using local notification then try:
// if launched by the local notification
var notification: UILocalNotification = (launchOptions[UIApplicationLaunchOptionsLocalNotificationKey] as! UILocalNotification)
if notification != nil {
}
来源:https://stackoverflow.com/questions/36709454/how-to-open-particular-post-on-the-click-on-push-notification