问题
I was trying to make a code that will check all messages in a channel for messages that contain certain words, and delete them if it does contain them. So something like:
if(msg.content.startsWith(prefix+'clean') {
let check = msg.content.split(prefix+'clean')[1]; // Condition, in this case if it containts a certain string
msg.channel.fetchMessages().then(msgs => { // Get messages to check
let msglog = msgs.array() // Make an array with all the messages fetched
for(var i = 0; i < msglog.size; i++) { // Loop to check all messages in array
if (check in msglog[i]) {
// Code to delete that message
};
};
});
};
I am aware that this will not check the entire channel and it will only check the last 50 messages, but I do not know how to make it check the whole channel so this will do until I find out how to do that.
But what code would delete the message that passes the check? Or any different way I could approach this?
Edit:
It seems I was not clear enough, so let's say a channel has the following conversation:
Person A: Hi, guys!
Person B: Hi
Person C: Bye
Let's say I want to delete all the messages with "Hi" in it through my bot, how should I do this? Note: I do not with to delete a message right after it has been sent, I only want to delete it when I want to do so.
回答1:
The bulkDelete function delete given messages that are newer than two weeks.
if(msg.content.startsWith(prefix+'clean') {
let check = msg.content.split(prefix+'clean')[1]; // Condition, in this case if it containts a certain string
msg.channel.fetchMessages().then(msgs => { // Get messages to check
let msgDel = msgs.filter(msgss => msgss.content.includes(check)) // Finds all messages with 'check'
msg.channel.bulkDelete(msgDel) // Deletes all messages that got found
});
};
To delete the messages older than 2 weeks, you have to iterate through the messages manually to delete them:
async function deleteReturnLast(chan, option, prevMsg, cond) {
return chan.fetchMessages(option)
.then(async msgs => {
if (msgs.size === 0){
if (cond(prevMsg)) {
prevMsg.delete()
.then(d => console.log('last message deleted: ' + d.content))
.catch(err => console.log('ERR>>', err, prevMsg.content, option.before)); }
return prevMsg;
};
let last = msgs.last();
for (const[id, msg] of msgs) {
let tmp = (id === last.id) ? prevMsg : msg;
if (cond(tmp)) {
tmp.delete()
.then(d => console.log('Message deleted: ' + d.content))
.catch(err => console.log('ERR>>', err));
}
};
return last;
})
.catch(err => console.log('ERR>>', err));
}
function cond(msg) {
return !msg.content.includes('a');
}
client.on('message', async function(msg) {
let chan = msg.channel;
let last = chan.lastMessage;
while (last !== (last = await deleteReturnLast(chan, {limit: 2, before: last.id}, last, cond))){
};
});
回答2:
Well, this is how I solved my problem after I realised the 2 week limitation of fetchMessages()
else if(msg.content.startsWith(`${prefix}clean`}) { // Check for command
let check = msg.content.split(`${prefix}clean`)[1] // Defines a check
msg.channel.fetchMessages({ limit: 100 }).then(msgs => { // Fetches the last 100 messages of the channel were the command was given
const msgstodelete = msgs.filter(del => del.content.includes(check)) // Filters the messages according to the check
msg.delete() // Deletes the original message with the command
for (var i = 0; i<Array.from(msgstodelete.keys()).length; i++) {
msg.channel.fetchMessage(Array.from(msgstodelete.keys())[i]).then(deldel => deldel.delete())
} // Loop to delete all messages that passed the filter
})
}
来源:https://stackoverflow.com/questions/56819979/search-a-given-discord-channel-for-all-messages-that-satisfies-the-condition-and