Multiple selection listbox of State not displaying all Cities in another listbox(Php,mysql,ajax)

问题

Selecting the Country dropdown displays State listbox with multiple selections without refreshing page . But selecting 2 or 3 States not displaying all cities in another lisbox. Cities are displaying for only one State. help

loadData.php

<?php
$q = $_GET['q'];
$con = mysqli_connect('localhost','root','','test');
if (!$con) {
  die('Could not connect: ' . mysqli_error($con));
}

mysqli_select_db($con,"test");
$sql="SELECT * FROM state WHERE country_id = '".$q."'";
$result = mysqli_query($con,$sql);
    echo "<select name='try[]' onchange='showSecondUser(this.value)' multiple>";
while($row = mysqli_fetch_array($result)){
          echo "<option value='".$row['id']."'>".$row['state_name']."</option>";
}
    echo" </select>";



$g = $_GET['g'];    
$sql="SELECT * FROM city WHERE state_id = '".$g."'";
$result = mysqli_query($con,$sql);
    echo "<select name='try' multiple>";
while($row = mysqli_fetch_array($result)){
          echo "<option value=''>".$row['city_name']."</option>";
}
    echo" </select>";

mysqli_close($con);
?>

index.php

<html>
<head>
<script>
function showUser(str) {
  if (str=="") {
    document.getElementById("txtHint").innerHTML="";
    return;
  }
  if (window.XMLHttpRequest) {
    // code for IE7+, Firefox, Chrome, Opera, Safari
    xmlhttp=new XMLHttpRequest();
  } else { // code for IE6, IE5
    xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
  xmlhttp.onreadystatechange=function() {
    if (xmlhttp.readyState==4 && xmlhttp.status==200) {
      document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
    }
  }
  xmlhttp.open("GET","loadData.php?q="+str,true);
  xmlhttp.send();
}


function showSecondUser(str) {
  if (str=="") {
    document.getElementById("txtHint2").innerHTML="";
    return;
  }
  if (window.XMLHttpRequest) {
    // code for IE7+, Firefox, Chrome, Opera, Safari
    xmlhttp=new XMLHttpRequest();
  } else { // code for IE6, IE5
    xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
  xmlhttp.onreadystatechange=function() {
    if (xmlhttp.readyState==4 && xmlhttp.status==200) {
      document.getElementById("txtHint2").innerHTML=xmlhttp.responseText;
    }
  }
  xmlhttp.open("GET","loadData.php?g="+str,true);
  xmlhttp.send();
}



</script>
</head>
<body>

<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select Country</option>
<option value="1">Australia</option>
<option value="2">Japan</option>
<option value="3">Russia</option>
<option value="4">Germany</option>
</select>
</form>
<br>
<div id="txtHint"></div>

<div id="txtHint2"></div>

</body>
</html>

回答1:

It' because mysql query is wrong. You providing multiple numbers in a simple equal.

That should be:

$g = $_GET['g'];    
$sql="SELECT * FROM city WHERE state_id IN (".$g.")";
$result = mysqli_query($con,$sql);

if $g is a comma separeted list of numbers. If not you have to make it so.

So if $g is an array you have to do an implode() on it and than you can use it in the query

$g = $_GET['g'];    
$g = implode(',', $g);
$sql="SELECT * FROM city WHERE state_id IN (".$g.")";
$result = mysqli_query($con,$sql);

if it is a string and lets say the numbers are separated my space than you replace space with comma:

$g = $_GET['g'];    
$g = str_replace(' ', ',', $g);
$sql="SELECT * FROM city WHERE state_id IN (".$g.")";
$result = mysqli_query($con,$sql);

So in your case the MySQL query should be this:

$sql="SELECT * FROM state WHERE country_id = '".$q."'";
$result = mysqli_query($con,$sql);
    echo "<select name='try[]' onchange='showSecondUser(this)' multiple>";
    //                            there is a change here ^
    while($row = mysqli_fetch_array($result)){
       echo "<option value='".$row['id']."'>".$row['state_name']."</option>";
    }
    echo" </select>";
/*######################################################*/
$g = $_GET['g'];    
$sql="SELECT * FROM city WHERE state_id IN (".$g.")";
$result = mysqli_query($con,$sql);

And the javascript should be this:

function showSecondUser(str){
    var xmlhttp;
    if (window.XMLHttpRequest) {
        xmlhttp = new XMLHttpRequest();
    } else {
        xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
    }
    xmlhttp.onreadystatechange = function () {
        if (xmlhttp.readyState === 4 && xmlhttp.status === 200) {
            document.getElementById("txtHint2").innerHTML = xmlhttp.responseText;
        }
    }

    var values = new Array();
    for (var i=0; i < str.options.length; i++) {
        cur = sel.options[i];
        if (cur.selected) {
            values.push(cur.value);
        }
    }
    if (values.length) {
        values = values.join(",");
    } else {
        values = null;
    }

    xmlhttp.open("GET","loadData.php?g="+values,true);
    xmlhttp.send();
}

来源：https://stackoverflow.com/questions/26305937/multiple-selection-listbox-of-state-not-displaying-all-cities-in-another-listbox

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javascript

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mysql

ajax

listbox