How to Extract the file name from a full path in bat?

问题

A variable %result% contains the path "D:\My Folder1\My Folder 2\My Folder 3\The Important File.txt" . I want to store The Important File in some another variable. That is, I want to extract the file name (Without extention) from a full path.

回答1:

This should give you what you need.

@echo off
for %%a in ("%result%") do set "newvariable=%%~na"

回答2:

You'll find a solution here: Get the file name from a full or relative path knowing that this one is not a parameter of the batch

here: Get filename from string-path?

here: In Batch: Read only the filename from a variable with path and filename

Please search existing questions before creating duplicates.

来源：https://stackoverflow.com/questions/21257407/how-to-extract-the-file-name-from-a-full-path-in-bat