问题
I'm trying to write a decorator that 'refreshes' after being called, but where the refreshing only occurs once after the last function exits. Here is an example:
@auto_refresh
def a():
print "In a"
@auto_refresh
def b():
print "In b"
a()
If a()
is called, I want the refresh function to be run after exiting a()
. If b()
is called, I want the refresh function to be run after exiting b()
, but not after a()
when called by b()
. Here is an example of a class that does this:
class auto_refresh(object):
def __init__(self, f):
print "Initializing decorator"
self.f = f
def __call__(self, *args, **kwargs):
print "Before function"
if 'refresh' in kwargs:
refresh = kwargs.pop('refresh')
else:
refresh = False
self.f(*args, **kwargs)
print "After function"
if refresh:
print "Refreshing"
With this decorator, if I run
b()
print '---'
b(refresh=True)
print '---'
b(refresh=False)
I get the following output:
Initializing decorator
Initializing decorator
Before function
In b
Before function
In a
After function
After function
---
Before function
In b
Before function
In a
After function
After function
Refreshing
---
Before function
In b
Before function
In a
After function
After function
So when written this way, not specifying the refresh
argument means that refresh is defaulted to False
. Can anyone think of a way to change this so that refresh
is True
when not specified? Changing the
refresh = False
to
refresh = True
in the decorator does not work:
Initializing decorator
Initializing decorator
Before function
In b
Before function
In a
After function
Refreshing
After function
Refreshing
---
Before function
In b
Before function
In a
After function
Refreshing
After function
Refreshing
---
Before function
In b
Before function
In a
After function
Refreshing
After function
because refresh then gets called multiple times in the first and second case, and once in the last case (when it should be once in the first and second case, and not in the last case).
回答1:
To count the number of "nestings", in a thread-safe way, is a good example of using thread-local storage:
import threading
mydata = threading.local()
mydata.nesting = 0
class auto_refresh(object):
def __init__(self, f):
self.f = f
def __call__(self, *args, **kwargs):
mydata.nesting += 1
try: return self.f(*args, **kwargs)
finally:
mydata.nesting -= 1
if mydata.nesting == 0:
print 'refreshing'
If you don't care about threading, as long as your installation of Python is compiled with threading enabled (and these days just about all of them are), this will still work just fine. If you fear a peculiar Python installation without threading, change the import
statement to
try:
import threading
except ImportError:
import dummy_threading as threading
roughly as recommended in the docs (except that the docs use a peculiar "private" name for the import's result, and there's no real reason for that, so I'm using a plain name;-).
回答2:
I think it might be simpler to maintain a "nested-refresh count" that is incremented before each refresh-decorated call and decremented after (in a finally block so that the count doesn't get messed up); run the refresh routine whenever the count hits zero.
回答3:
It's not clear to me exactly what you're attempting to use this design for, and because of that, whether it's a good idea or not. Consider whether or not it's the right approach.
However, I think this does what you requested. A common object (named auto_refresh
in this case) is shared by all 'decorated' methods, and that object keeps a counter as to how deep the call stack is.
This is not thread-safe.
class AutoRefresh(object):
nesting = 0
def __call__(self, f):
def wrapper(*args, **kwargs):
return self.proxied_call(f, args, kwargs)
return wrapper
def refresh(self):
print 'refresh'
def proxied_call(self, func, args, kwargs):
self.nesting += 1
result = func(*args, **kwargs)
self.nesting -= 1
if self.nesting == 0:
self.refresh()
return result
auto_refresh = AutoRefresh()
Tested with:
@auto_refresh
def a():
print "In a"
@auto_refresh
def b():
print "In b"
a()
a()
print '---'
b()
Resulting in:
In a
refresh
---
In b
In a
refresh
来源:https://stackoverflow.com/questions/2529592/refresh-decorator