问题
I want to draw the two semi circles like this as shown in picture (the below one)
I'm trying it but did not get anything. Tried some chart api and a few code to draw pie chart from stackoverflow but they need to edit and I don't know about Core Graphics. I am working on Xcode 7.3.1 and iOS 9.
My Question is:
How do I draw a semi-circle which take one value and first convert that value to get its equivalent angle and then draw an arc of this angle and fill color in that part?
回答1:
The below code runs in the XCode iOS Playground. It creates a custom UIView
class and draws two pie slices. The start and end angle are specified in percent of a full circle.
You can easily extend it to display more or less slices depending on the data you have.
The drawRect
method creates a bezier path that starts in the center, then adds an arc segment and finally closes the path so it can be filled.
Xcode 10.2.1/Swift 4.2 Update
class PieChart : UIView {
override func draw(_ rect: CGRect) {
drawSlice(rect: rect, startPercent: 0, endPercent: 50, color: .green)
drawSlice(rect: rect, startPercent: 50, endPercent: 75, color: .red)
}
private func drawSlice(rect: CGRect, startPercent: CGFloat, endPercent: CGFloat, color: UIColor) {
let center = CGPoint(x: rect.origin.x + rect.width / 2, y: rect.origin.y + rect.height / 2)
let radius = min(rect.width, rect.height) / 2
let startAngle = startPercent / 100 * CGFloat.pi * 2 - CGFloat.pi
let endAngle = endPercent / 100 * CGFloat.pi * 2 - CGFloat.pi
let path = UIBezierPath()
path.move(to: center)
path.addArc(withCenter: center, radius: radius, startAngle: startAngle, endAngle: endAngle, clockwise: true)
path.close()
color.setFill()
path.fill()
}
}
let pieChart = PieChart(frame: CGRect(x: 0.0, y: 0.0, width: 300.0, height: 300.0))
pieChart.backgroundColor = .clear
An Unnamed Earlier Version
import UIKit
class PieChart : UIView {
override func drawRect(rect: CGRect) {
drawSlice(rect, startPercent: 0, endPercent: 50, color: UIColor.greenColor())
drawSlice(rect, startPercent: 50, endPercent: 75, color: UIColor.redColor())
}
private func drawSlice(rect: CGRect, startPercent: CGFloat, endPercent: CGFloat, color: UIColor) {
let center = CGPoint(x: rect.origin.x + rect.width / 2, y: rect.origin.y + rect.height / 2)
let radius = min(rect.width, rect.height) / 2
let startAngle = startPercent / 100 * CGFloat(M_PI) * 2 - CGFloat(M_PI)
let endAngle = endPercent / 100 * CGFloat(M_PI) * 2 - CGFloat(M_PI)
let path = UIBezierPath()
path.moveToPoint(center)
path.addArcWithCenter(center, radius: radius, startAngle: startAngle, endAngle: endAngle, clockwise: true)
path.closePath()
color.setFill()
path.fill()
}
}
let pieChart = PieChart(frame: CGRect(x: 0.0, y: 0.0, width: 300.0, height: 300.0))
pieChart.backgroundColor = UIColor.clearColor()
回答2:
My issue has been resolved.
We just need to do a little change in the first line to make it like as in picture's semicircle:
drawSlice(rect, startPercent: 0, endPercent: 50, color: UIColor.greenColor())
drawSlice(rect, startPercent: 0, endPercent: 25, color: UIColor.redColor())
回答3:
Codo's code in Swift 3:
import UIKit
class PieChart : UIView {
override func draw(_ rect: CGRect) {
drawSlice(rect, startPercent: 0, endPercent: 50, color: .green)
drawSlice(rect, startPercent: 50, endPercent: 75, color: .red)
}
private func drawSlice(_ rect: CGRect, startPercent: CGFloat, endPercent: CGFloat, color: UIColor) {
let center = CGPoint(x: rect.origin.x + rect.width / 2, y: rect.origin.y + rect.height / 2)
let radius = min(rect.width, rect.height) / 2
let startAngle = startPercent / 100 * CGFloat.pi * 2 - CGFloat.pi
let endAngle = endPercent / 100 * CGFloat.pi * 2 - CGFloat.pi
let path = UIBezierPath()
path.move(to: center)
path.addArc(withCenter: center, radius: radius, startAngle: startAngle, endAngle: endAngle, clockwise: true)
path.close()
color.setFill()
path.fill()
}
}
let pieChart = PieChart(frame: CGRect(x: 0.0, y: 0.0, width: 300.0, height: 300.0))
pieChart.backgroundColor = UIColor.clear
来源:https://stackoverflow.com/questions/38259673/how-to-draw-a-semi-circle-using-swift-ios-9-and-on-the-basis-of-one-value-draw-a