PHP: call_user_func_array: pass by reference issue

问题

The below function generates error when a function contains referenced arguments eg:

function test(&$arg, &$arg2)
{
  // some code
}

Now I can not use call_user_func_array for above function, it will generate an error.

How to solve this problem?

I do need to use call_user_func_array.

Also assume that i don't know beforehand whether they are passed by reference or passed by value.

Thanks

回答1:

A great workaround was posted on http://www.php.net/manual/de/function.call-user-func-array.php#91503

function executeHook($name, $type='hooks'){ 
    $args = func_get_args(); 
    array_shift($args); 
    array_shift($args); 
    //Rather stupid Hack for the call_user_func_array(); 
    $Args = array(); 
    foreach($args as $k => &$arg){ 
        $Args[$k] = &$arg; 
    } 
    //End Hack 
    $hooks = &$this->$type; 
    if(!isset($hooks[$name])) return false; 
    $hook = $hooks[$name]; 
    call_user_func_array($hook, $Args); 
} 

The actual hack is surrounded by comments.

回答2:

When storing your parameters in the array, make sure you are storing a reference to those parameters, it should work fine.

Ie:

call_user_func_array("test", array(&param1, &param2));

来源：https://stackoverflow.com/questions/1905800/php-call-user-func-array-pass-by-reference-issue