问题
I wanted to get all unique pairwise combinations of a unique string column of a dataframe using the tidyverse
(ideally).
Here is a dummy example:
library(tidyverse)
a <- letters[1:3] %>%
tibble::as_tibble()
a
#> # A tibble: 3 x 1
#> value
#> <chr>
#> 1 a
#> 2 b
#> 3 c
tidyr::crossing(a, a) %>%
magrittr::set_colnames(c("words1", "words2"))
#> # A tibble: 9 x 2
#> words1 words2
#> <chr> <chr>
#> 1 a a
#> 2 a b
#> 3 a c
#> 4 b a
#> 5 b b
#> 6 b c
#> 7 c a
#> 8 c b
#> 9 c c
Is there a way to remove 'duplicate' combinations here. That is have the output be the following in this example:
# A tibble: 9 x 2
#> words1 words2
#> <chr> <chr>
#> 1 a b
#> 2 a c
#> 3 b c
I was hoping there would be a nice purrr::map
or filter
approach to pipe into to complete the above.
EDIT: There are similar questions to this one e.g. here, marked by @Sotos. Here I am specifically looking for tidyverse (purrr
, dplyr
) ways to complete the pipeline I have setup. The other answers use various other packages that I do not want to include as dependencies.
回答1:
wish there was a better way, but I usually use this...
library(tidyverse)
df <- tibble(value = letters[1:3])
df %>%
expand(value, value) %>%
filter(value < value1)
# # A tibble: 3 x 2
# value value1
# <chr> <chr>
# 1 a b
# 2 a c
# 3 b c
回答2:
Something like this?
tidyr::crossing(a, a) %>%
magrittr::set_colnames(c("words1", "words2")) %>%
rowwise() %>%
mutate(words1 = sort(c(words1, words2))[1], # sort order of words for each row
words2 = sort(c(words1, words2))[2]) %>%
filter(words1 != words2) %>% # remove word combinations with itself
unique() # remove duplicates
# A tibble: 3 x 2
words1 words2
<chr> <chr>
1 a b
2 a c
3 b c
来源:https://stackoverflow.com/questions/46491410/tidyr-unique-way-to-get-combinations-using-tidyverse-only