问题
I asked a similar question to this already, but I still can't see the problem?
-(id)initWithKeyPadType: (int)value
{
[self setKeyPadType:value];
self = [self init];
if( self != nil )
{
//self.intKeyPadType = value;
}
return self;
}
- (id)init {
NSNumberFormatter *formatter = [[[NSNumberFormatter alloc] init]
autorelease];
decimalSymbol = [formatter decimalSeparator];
....
The warning comes from the line above Instance variable used while 'self' is not set to the result of '[(super or self) init...]'
回答1:
What you are trying to do is technically OK, but at some stage you need to invoke [super init]. If your class's init method does a lot of common initialisation that other initWith... methods utilise, then put your [super init] in there. Also, always make sure that the class has been init'd before trying to play around with instance variables.
- (id) initWithKeyPadType: (int)value
{
self = [self init]; // invoke common initialisation
if( self != nil )
{
[self setKeyPadType:value];
}
return self;
}
- (id) init
{
self = [super init]; // invoke NSObject initialisation (or whoever superclass is)
if (!self) return nil;
NSNumberFormatter *formatter = [[[NSNumberFormatter alloc] init]
autorelease];
decimalSymbol = [formatter decimalSeparator];
...
回答2:
The warning means what it says. You are assigning something to decimalSymbol, which is an instance variable, but at that point there is no instance. You need a
self = [super init];
At the start of your init method. At some point the object has to be created, at some point this has to call back to NSObject (via a chain of super inits).
来源：https://stackoverflow.com/questions/8086996/obj-instance-variable-used-when-self-is-not-set-to-the-result-of-super-or