c++ deleted move assignment operator compilation issues

问题

The following code fails with gcc 4.8.0 (mingw-w64) with -O2 -std=c++11 -frtti -fexceptions -mthreads

#include <string>

class Param
{
public:
    Param() : data(new std::string) { }

    Param(const std::string & other) : data(new std::string(other)) { }

    Param(const Param & other) : data(new std::string(*other.data)) { }

    Param & operator=(const Param & other) {
        *data = *other.data; return *this;
    }

    ~Param() {
        delete data;
    }

    Param & operator=(Param &&) = delete;


private:
    std::string * data;
};


int main()
{
    Param param;
    param = Param("hop");


    return 0;
}

With the error : error: use of deleted function 'Param& Param::operator=(Param&&)' On the line :

param = Param("hop");

And compiles well if I remove the move assignment delete line.

There should be no default move assignment operator since there are user defined copy constructors, user defined copy assignment, and destructors, so deleting it should not affect the compilation, why is it failing? And why is the allocation simply not using a copy assignment?

回答1:

The function you deleted is exactly the assignment operator you try to use in main. By explicitly defining it as deleted you declare it and at the same time say using it is an error. So when you try to assign from an rvalue (Param("hop")), the compiler first looks whether a move assignment operator was declared. Since it was and is the best match, it tries to use it, just to find that it was deleted. Thus the error.

Here's another example of this mechanism which uses no special functions:

class X
{
  void f(int) {}
  void f(short) = delete;
};

int main()
{
  X x;
  short s;
  x.f(s);  // error: f(short) is deleted.
}

Removing the deleted f(short) will cause the compiler to select the non-deleted f(int) and thus compile without error.

来源：https://stackoverflow.com/questions/23000243/c-deleted-move-assignment-operator-compilation-issues