Initialize a 2D array of unknown size using macros in C

问题

I was working on a small macro project that requires me to pass a 2 dimensional array literal to one of my macros like so: myMacro({{0, 1, 2}, {2, 1, 0}}). Without having to pass the size of the array literal to the macro, is there a way to have it expand to the following: int[2][3] = { {0, 1, 2}, {2, 1, 0} } or something equivalent (any initialization that preserves the shape of the array will work)? Thanks in advance for any help

回答1:

#include <boost/preprocessor/tuple/size.hpp>
#include <boost/preprocessor/tuple/elem.hpp>
#include <boost/preprocessor/variadic/to_seq.hpp>
#include <boost/preprocessor/seq/for_each.hpp>

#define VA(...) __VA_ARGS__
#define TRANS(r, data, elem) { VA elem},

#define myMacro(name, arg)\
    int name[BOOST_PP_TUPLE_SIZE(arg)][BOOST_PP_TUPLE_SIZE(BOOST_PP_TUPLE_ELEM(0,arg))] = \
    { BOOST_PP_SEQ_FOR_EACH(TRANS, , BOOST_PP_VARIADIC_TO_SEQ arg)}

int main(){
    myMacro(a, ((1,2,3),(4,5,6)) );//=>int a[2][3] = { { 1,2,3}, { 4,5,6}, };
    return 0;
}

回答2:

If you have an upper limit for the second dimension then you could use sentinel values such as:

#include <stdio.h>

#define MAXCOLUMNS 20
#define VALUE {{0,1,2,-1},{2,3,4,-1},{0,0,0,0,1,-1},{-1}}

int main()
{
  int v[][MAXCOLUMNS] = VALUE;
  int x, y;

  for (y = 0; v[y][0] != -1; y++)
    for (x = 0; v[y][x] != -1; x++)
      printf("[%d,%d] = %d\n", x, y, v[y][x]);

  return 0;
}

This will print out the values without knowing the exact dimensions beforehand. Is this something you are trying to achieve?

Edit: @BLUEPIXYs solution doesn't require knowing or guessing maximum dimensions, on the other hand this works with older C versions (not a big concern, though).

来源：https://stackoverflow.com/questions/27784649/initialize-a-2d-array-of-unknown-size-using-macros-in-c

标签

arrays

multidimensional-array

c-preprocessor