css increment nth-child attribute values

问题

Is there a way to increment attribute values using n in nth-child(n) to output the result of:

div:nth-child(1){
    top: -5px;
}
div:nth-child(2){
    top: -10px;
}
div:nth-child(3){
    top: -15px;
}
div:nth-child(4){
    top: -20px;
}
div:nth-child(5){
    top: -25px;
}

回答1:

You could if you use a preprocessor like sass.

An example:

div {
  $var: 5;

  @for $i from 1 through 5 {
    &:nth-child(#{$i}) {
      top: -#{$var}px;
      $var: $var + 5;
    }
  }
}

A demo: http://sassmeister.com/gist/7d7a8ed86e857be02d1a

Another way to achieve this:

div {

  $list: 1 2 3 4 5;

  @each $i in $list {
    &:nth-child(#{$i}) {
      top: -5px * $i;
    }
  }
}

A demo: https://www.sassmeister.com/gist/fb5ee7aa774aafb896cd71a828882b99

来源：https://stackoverflow.com/questions/26973340/css-increment-nth-child-attribute-values